我想尝试转换这样的时间戳:
2015-06-27T09:34:22+00:00
到格式的时间所以它会说像9个月前1天2小时30分2秒.
类似的东西.
我使用time.Parse并time.Since达到这个目的:
6915h7m47.6901559s
但是我如何从那里转换？这样的事情就是我想的:
for hours > 24 {
days++
hours -= 24
}
但问题是,这个月不准确,因为几个月可能有28天,30天和31天.
有没有更好的方法来实现我想要的？
icz*_*cza 40
一个月的日子取决于日期,就像一年中的日子(闰年).
如果time.Since()用于获取自time.Time值以来经过的时间,或者time.Time使用该Time.Sub()方法计算2个值之间的差值,则结果time.Duration将丢失时间上下文(Duration仅为纳秒时间差).这意味着您无法准确无误地计算数值与年份,月份等的差异Duration.
正确的解决方案必须计算时间背景的差异.您可以计算每个字段(年,月,日,小时,分钟,秒)的差异,然后将结果标准化为不具有任何负值.Time如果它们之间的关系不是预期的,也建议交换值.
标准化意味着如果值为负,则添加该字段的最大值并将下一个字段减1.例如,如果seconds为负,则添加60到它并递减minutes1.要注意的一件事是规范化天数的差异(每月的天数),必须应用适当月份的天数.这可以通过这个小技巧轻松计算:
// Max days in year y1, month M1
t := time.Date(y1, M1, 32, 0, 0, 0, 0, time.UTC)
daysInMonth := 32 - t.Day()
这背后的逻辑是,这一天32比任何一个月的最大日都要大.它将自动标准化(额外的天数滚动到下个月和日正确递减).当我们从32减去标准化之后的日子时,我们得到了该月的最后一天.
时区处理:
如果我们传入的两个时间值都在同一时区(time.Location)中,差异计算将只给出正确的结果.我们将检查结合到我们的函数中:如果不是这种情况,我们使用该Time.In()方法将其中一个时间值"转换"为与另一个相同的位置:
if a.Location() != b.Location() {
b = b.In(a.Location())
}
这是一个计算年,月,日,小时,分钟,秒差异的解决方案:
func diff(a, b time.Time) (year, month, day, hour, min, sec int) {
if a.Location() != b.Location() {
b = b.In(a.Location())
}
if a.After(b) {
a, b = b, a
}
y1, M1, d1 := a.Date()
y2, M2, d2 := b.Date()
h1, m1, s1 := a.Clock()
h2, m2, s2 := b.Clock()
year = int(y2 - y1)
month = int(M2 - M1)
day = int(d2 - d1)
hour = int(h2 - h1)
min = int(m2 - m1)
sec = int(s2 - s1)
// Normalize negative values
if sec < 0 {
sec += 60
min--
}
if min < 0 {
min += 60
hour--
}
if hour < 0 {
hour += 24
day--
}
if day < 0 {
// days in month:
t := time.Date(y1, M1, 32, 0, 0, 0, 0, time.UTC)
day += 32 - t.Day()
month--
}
if month < 0 {
month += 12
year--
}
return
}
一些测试:
var a, b time.Time
a = time.Date(2015, 5, 1, 0, 0, 0, 0, time.UTC)
b = time.Date(2016, 6, 2, 1, 1, 1, 1, time.UTC)
fmt.Println(diff(a, b)) // Expected: 1 1 1 1 1 1
a = time.Date(2016, 1, 2, 0, 0, 0, 0, time.UTC)
b = time.Date(2016, 2, 1, 0, 0, 0, 0, time.UTC)
fmt.Println(diff(a, b)) // Expected: 0 0 30 0 0 0
a = time.Date(2016, 2, 2, 0, 0, 0, 0, time.UTC)
b = time.Date(2016, 3, 1, 0, 0, 0, 0, time.UTC)
fmt.Println(diff(a, b)) // Expected: 0 0 28 0 0 0
a = time.Date(2015, 2, 11, 0, 0, 0, 0, time.UTC)
b = time.Date(2016, 1, 12, 0, 0, 0, 0, time.UTC)
fmt.Println(diff(a, b)) // Expected: 0 11 1 0 0 0
输出符合预期:
1 1 1 1 1 1
0 0 30 0 0 0
0 0 28 0 0 0
0 11 1 0 0 0
在Go Playground尝试一下.
要计算你的年龄:
// Your birthday: let's say it's January 2nd, 1980, 3:30 AM
birthday := time.Date(1980, 1, 2, 3, 30, 0, 0, time.UTC)
year, month, day, hour, min, sec := diff(birthday, time.Now())
fmt.Printf("You are %d years, %d months, %d days, %d hours, %d mins and %d seconds old.",
year, month, day, hour, min, sec)
示例输出:
You are 36 years, 3 months, 8 days, 11 hours, 57 mins and 41 seconds old.
Go游乐场时间开始的神奇日期/时间是:2009-11-10 23:00:00 UTC
这是Go首次宣布的时间.我们来算一下Go的年龄:
goAnnounced := time.Date(2009, 11, 10, 23, 0, 0, 0, time.UTC)
year, month, day, hour, min, sec := diff(goAnnounced, time.Now())
fmt.Printf("Go was announced "+
"%d years, %d months, %d days, %d hours, %d mins and %d seconds ago.",
year, month, day, hour, min, sec)
输出:
Go was announced 6 years, 4 months, 29 days, 16 hours, 53 mins and 31 seconds ago.
izca提出的解决方案很棒，但它遗漏了一件事。如果添加如下示例，可以看到效果：
a = time.Date(2015, 1, 11, 0, 0, 0, 0, time.UTC)
b = time.Date(2015, 3, 10, 0, 0, 0, 0, time.UTC)
fmt.Println(diff(a, b))
// Expected: 0 1 27 0 0 0
// Actual output: 0 1 30 0 0 0
代码是根据第一个月的总天数 ( y1,M1)计算下一个不完整月份的剩余天数，但需要从较晚日期月份 ( y2,M2-1)的前一个月开始计算。
最终代码如下：
package main
import (
"fmt"
"time"
)
func DaysIn(year int, month time.Month) int {
return time.Date(year, month+1, 0, 0, 0, 0, 0, time.UTC).Day()
}
func Elapsed(from, to time.Time) (inverted bool, years, months, days, hours, minutes, seconds, nanoseconds int) {
if from.Location() != to.Location() {
to = to.In(to.Location())
}
inverted = false
if from.After(to) {
inverted = true
from, to = to, from
}
y1, M1, d1 := from.Date()
y2, M2, d2 := to.Date()
h1, m1, s1 := from.Clock()
h2, m2, s2 := to.Clock()
ns1, ns2 := from.Nanosecond(), to.Nanosecond()
years = y2 - y1
months = int(M2 - M1)
days = d2 - d1
hours = h2 - h1
minutes = m2 - m1
seconds = s2 - s1
nanoseconds = ns2 - ns1
if nanoseconds < 0 {
nanoseconds += 1e9
seconds--
}
if seconds < 0 {
seconds += 60
minutes--
}
if minutes < 0 {
minutes += 60
hours--
}
if hours < 0 {
hours += 24
days--
}
if days < 0 {
days += DaysIn(y2, M2-1)
months--
}
if months < 0 {
months += 12
years--
}
return
}
func main() {
var a, b time.Time
a = time.Date(2015, 5, 1, 0, 0, 0, 0, time.UTC)
b = time.Date(2016, 6, 2, 1, 1, 1, 1, time.UTC)
fmt.Println(Elapsed(a, b)) // Expected: false 1 1 1 1 1 1
a = time.Date(2016, 1, 2, 0, 0, 0, 0, time.UTC)
b = time.Date(2016, 2, 1, 0, 0, 0, 0, time.UTC)
fmt.Println(Elapsed(a, b)) // Expected: false 0 0 30 0 0 0
a = time.Date(2016, 2, 2, 0, 0, 0, 0, time.UTC)
b = time.Date(2016, 3, 1, 0, 0, 0, 0, time.UTC)
fmt.Println(Elapsed(a, b)) // Expected: false 0 0 28 0 0 0
a = time.Date(2015, 2, 11, 0, 0, 0, 0, time.UTC)
b = time.Date(2016, 1, 12, 0, 0, 0, 0, time.UTC)
fmt.Println(Elapsed(a, b)) // Expected: false 0 11 1 0 0 0
a = time.Date(2015, 1, 11, 0, 0, 0, 0, time.UTC)
b = time.Date(2015, 3, 10, 0, 0, 0, 0, time.UTC)
fmt.Println(Elapsed(a, b)) // Expected: false 0 1 27 0 0 0
}