如何自定义 TreeMap 以按降序对键进行排序?

Sek*_*har 0 java sorting treemap

我有一段代码,我试图用它按TreeMap降序对键进行排序,因为当我只使用 时TreeMap,它会根据按升序排列的键进行排序。我收到的错误是:

没有找到适合 TreeMap 的构造函数。

这是怎么回事?

import java.util.TreeMap;
import java.util.Map;
import java.util.Comparator;
import java.util.Map.Entry;
import java.util.SortedMap;

public class ChangeMachine {


    public TreeMap<Double, Integer> dispenseChange(Double changeAmount, TreeMap<Double, Integer> coinsMap) {
        TreeMap<Double, Integer> coinDispenserMap = new TreeMap<>();
        for (Map.Entry<Double, Integer> coin : coinsMap.entrySet()) {
            if (!(changeAmount > coin.getKey())) {
                coinDispenserMap.put(coin.getKey(), 0);
                continue;
            }
            int noOfCoins = (int) (changeAmount / coin.getKey());
            coinDispenserMap.put(coin.getKey(), noOfCoins);
            Double remainder = changeAmount % coin.getKey();
            changeAmount = remainder;
            if (changeAmount == 0.0) {
                break;
            }
        }
        return coinDispenserMap;

    }


    public static void main(String[] args) {
        ChangeMachine ref = new ChangeMachine();
        TreeMap<Double, Integer> coinsMap = new TreeMap<Double, Integer>(new Comparator<Entry<Double, Integer>>() {
            public int compare(Entry<Double, Integer> coin1, Entry<Double, Integer> coin2) {
                return (coin2.getKey().compareTo(coin1.getKey()));
            }
        });
        coinsMap.put(0.25, 10);
        coinsMap.put(0.01, 10);
        coinsMap.put(0.05, 10);
        coinsMap.put(0.10, 10);

        TreeMap<Double, Integer> coinDispenserMap = ref.dispenseChange(0.86, coinsMap);

        for (Map.Entry<Double, Integer> coin : coinDispenserMap.entrySet()) {
            System.out.println(coin.getKey() + " : " + coin.getValue());
        }
    }
}
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Han*_*k D 5

尝试这个:

Comparator<Double> comparator = Double::compare;
Comparator<Double> reverseComparator = comparator.reversed();
Map<Double,Integer> reversedMap = new TreeMap(reverseComparator);
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