Django中的可排序表

Question

我阅读了一些关于此的其他帖子以及一些涉及javascript和使用其他库的建议.我手动快速做了一些事情,但是我是Django和Python的新手,所以我很好奇这是不是一个好方法.

HTML

 <table>
        <tr>
            <td><a href="?sort=to">To</a></td>
            <td><a href="?sort=date">Date</a></td>
            <td><a href="?sort=type">Type</a></td>
        </tr>
        {% for record in records %}
        <tr><td>{{record.to}}</td><td>{{record.date}}</td><td>{{record.type}}</td></tr>
        {% endfor %}
    </table>

视图

headers = {'to':'asc',
         'date':'asc',
         'type':'asc',}

def table_view(request):
    sort = request.GET.get('sort')
    if sort is not None:
        if headers[sort] == "des":
            records = Record.objects.all().order_by(sort).reverse()
            headers[sort] = "asc"
        else:
            records = Record.objects.all().order_by(sort) 
            headers[sort] = "des"
    else:
        records = Record.objects.all()
    return render_to_response("table.html",{'user':request.user,'profile':request.user.get_profile(),'records':records})

Answer 1

在我看来很好。我建议在视图代码中进行一项小的重构：

headers = {'to':'asc',
         'date':'asc',
         'type':'asc',}

def table_view(request):
    sort = request.GET.get('sort')
    records = Record.objects.all()

    if sort is not None:
        records = records.order_by(sort)

        if headers[sort] == "des":
            records = records.reverse()
            headers[sort] = "asc"
        else:
            headers[sort] = "des"

    return render_to_response(...)