嵌套关系序列化器中的Django Rest Framework模型Id字段

use*_*500 16 python django rest django-rest-framework

我使用Django Rest Framework,我有以下两个序列化器:

class ServiceSerializer(serializers.ModelSerializer):
    id = serializers.ReadOnlyField()

    class Meta:
        model = ServiceType
        fields = ('id', 'serviceName', 'servicePrice')


class CompanyShortListSerializer(serializers.ModelSerializer):

     services = ServiceSerializer(many=True)

     class Meta:
         model = Company
         fields = ( 'id','name','address','cost_per_patient','cost_per_month','renting_fee','services')
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ServiceType模型如下所示:

class ServiceType(models.Model):
     serviceName = EncryptedCharField(max_length=100, blank=True, verbose_name = "Typ us?ugi")
     servicePrice = EncryptedFloatField(null=True, blank=True, verbose_name = "Cena us?ugi", validators = [MinValueValidator(0.1), MaxValueValidator(999)])
     company = models.ForeignKey(Company, related_name = 'services')
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我想通过更改相关服务来更新现有实例(例如删除其中一些).要做到这一点,我这样做:

def update(self, instance, validated_data):
    # Updates an exisitng Company with several services 
    instance.name = validated_data['name']
    instance.address = validated_data['address']
    instance.cost_per_patient = validated_data['cost_per_patient']
    instance.renting_fee = validated_data['renting_fee']
    services_data = validated_data['services']

    for item in services_data:
        updatedService = ServiceType(
            serviceName = item['serviceName'],
            servicePrice = item['servicePrice'],
            id=item['id'], 
            company=instance)
        updatedService.save()

    return instance
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我面临的问题service['id']是没有提供该字段 - 这意味着我得到了KeyError 'id'- 尽管我在ServiceSerializer id字段中明确地添加了它.

编辑

以下是我发布的示例性请求(取自Chrome):

 { "id":49,"name":"Test 1",
   "address":"Testowa 1",
   "renting_fee":200,
   "cost_per_month":300,
   "cost_per_patient":null,
   "services":[
   {"id":67,"serviceName":"Terapia","servicePrice":100},
   {"id":68,"serviceName":"Terapia par","servicePrice":150},
   {"id":69,"serviceName":"Terapia po angielsku","servicePrice":120}
   ]
 } 
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我做错了什么以及如何使用嵌套序列化器获取对象的ID(基本上是ServiceSerializer)?

编辑2号

当我从序列化程序更新功能打印时,我得到以下内容:

print(self.data['services']) 给我:

[
 OrderedDict([('id', 67), ('serviceName', u'Terapia'), ('servicePrice', 100.0)]),
 OrderedDict([('id', 68), ('serviceName', u'Terapia par'), ('servicePrice', 150.0)]),
 OrderedDict([('id', 69), ('serviceName', u'Terapia po angielsku'), ('servicePrice', 120.0)]), 
 OrderedDict([('id', 70), ('serviceName', u'Terapia grupowa'), ('servicePrice', 140.0)])
]
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但是,print(services_data)给出以下内容(基本相同,但没有id):

[
OrderedDict([(u'serviceName', u'Terapia'), (u'servicePrice', 100.0)]),
OrderedDict([(u'serviceName', u'Terapia par'), (u'servicePrice', 150.0)]),
OrderedDict([(u'serviceName', u'Terapia po angielsku'), (u'servicePrice', 120.0)])
]
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ids迷路...

编辑3

根据Django Rest Framework文档如果某个字段将在序列化器输出表示中,它应该是a HiddenField.然而,这需要一个default值...我已经检查过并且确实使用这个HiddenField,默认值'解决'问题 - 在validated_data中有ID.问题是这id是不正确的.是否有可能将此id值设置为发送到序列化程序的对象的值?

use*_*500 23

好的 - 我想我找到了答案......仔细阅读文档 :)

所以根据文档,id可以将字段设置为ModelField,如下所示:

id = serializers.ModelField(model_field=ServiceType()._meta.get_field('id'))
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实际上,添加此行后,该id字段存在于validated_data中:)

  • 谢谢,你救了我的一天:-) (4认同)

Cor*_*ory 15

接受的答案有效,但不必要地复杂化.您只需将ID字段更改为不只读即可.像这样的事情会做:

id = serializers.IntegerField(required=False)
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