续集更新事务

Was*_*mad 8 transactions node.js sequelize.js

我在Nodejs中使用sequalize事务,但我的问题是它不会users在Transaction中占用我的表并更新我的表

return sequelize.transaction(function (t) {
    var Users = objAllTables.users.users();
    return Users.update(updateUser, {
        where: {
            uid: sessionUser.uid,
            status: 'ACTIVE'
        }
    },{ transaction: t }).then(function (result) {

       return Utils.sendVerificationEmail(sessionUser.uid, sessionUser.user_email)
            .then(function(data){
                 data = false;  
                if(data == false){
                        throw new Error('Failed Email');
                }

            });


    }).then(function (result) {
        console.log(result);
        // Transaction has been committed
        // result is whatever the result of the promise chain returned to the transaction callback
    })

}).catch(function(err){
    res.send({message:err.message})
})
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安慰:

Executing (ad5247bd-18b8-4c6f-bb30-92744c7a5ac8): START TRANSACTION;
Executing (ad5247bd-18b8-4c6f-bb30-92744c7a5ac8): SET SESSION TRANSACTION ISOLATION LEVEL REPEATABLE READ;
Executing (ad5247bd-18b8-4c6f-bb30-92744c7a5ac8): SET autocommit = 1;
Executing (default): UPDATE `users` SET `username`='edited' WHERE `uid` = 20 AND `status` = 'ACTIVE'
Executing (ad5247bd-18b8-4c6f-bb30-92744c7a5ac8): ROLLBACK;
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正如您在控制台中看到的更新查询用完了事务

Sha*_*yar 25

transaction密钥必须在options:

return Users.update(updateUser, {
        where: {
            uid: sessionUser.uid,
            status: 'ACTIVE'
        },
        transaction: t     //second parameter is "options", so transaction must be in it
    })
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  • @AhmerSaeed`troy`只需要1个参数,你必须传递其中的所有选项.*ie*`users.destroy({where:{id:57},transaction:t})` (5认同)
  • 对于任何搜索此内容的人(因为我偶尔会这样做),可以在这里找到更新功能的续集文档(因为在我看来,Google 并不总是找到它):https://sequelize.org/master/class /lib/model.js~Model.html#static-method-update (2认同)