Ste*_*art 3 plot regression r glm logistic-regression
我想编写用于绘制逻辑回归模型的代码,即"S"形逻辑曲线.怎么可以这样做,因为我有两个独立的协变量?我正在附加我的数据集和我的模型的代码.先感谢您.
239 0.72 1
324.6 0.83 1
331.8 0.95 1
334.3 0.83 1
259.7 0.89 1
212.3 0.88 1
204.7 0.65 1
253.86 0.75 1
258.94 0.85 1
329.66 0.95 0
469.68 1.46 0
459.74 1.11 0
293.2 0.64 0
297.88 0.98 0
267.9 0.82 0
374.1 1.29 0
333.62 0.74 0
dat <- read.table("data.txt")
colnames(dat)<-c("press","v","gender")
# logostic regression
dat$gender <- factor(dat$gender)
mylogit<- glm(gender~press+v,data=dat,family="binomial")
summary(mylogit)
######## the code below are irrelevant to making plot, ignore if you want
mylogit$fitted.values
newdat <- data.frame(t(c(300,0.1)))
colnames(newdat)<-c("press","v")
# this is your new dataset, we name it as "newdat"
pred <- predict(mylogit,newdata = newdat,type="response")
pred # the probability of being in class 1 will stored in this object
pred <- predict(mylogit,newdata = dat,type="response")
pred # the probability of being in class 1 will stored in this object
# accuracy
dat$pred <- 0
factor(dat$pred)
dat$pred[which(pred>0.5)] <- 1
table(dat$gender,dat$pred)
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李哲源*_*李哲源 11
您有2个连续的非分类变量,因此逻辑曲线将是3D曲线.我将为您提供两种演示方式.
persp函数产生真实的3D平滑曲线;v多个值,然后产生一些2D逻辑曲线(你称之为"S"形曲线).3D曲线
press_grid <- seq(200, 480, by = 5)
v_grid <- seq(0.6, 1.5, by = 0.1)
newdat <- data.frame(press = rep(press_grid, times = length(v_grid)), v = rep(v_grid, each = length(press_grid)))
pred <- predict.glm(mylogit, newdata = newdat, type="response")
z <- matrix(pred, length(press_grid))
persp(press_grid, v_grid, z, xlab = "pressure", ylab = "velocity", zlab = "predicted probability", main = "logistic curve (3D)", theta = 30, phi = 20)
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您需要先生成2D网格.在newdat持有该网格,你可以plot(newdat)看到这样的网格.然后通过调用在此网格上进行预测predict.glm(..., type = "response").结果pred是一个向量.要绘制它,将其投射到矩阵z,然后调用persp以制作3D绘图.xlab,ylab并且zlab是三轴的标签.参数theta和phi用于调整您的视角.
在上面,边缘网格为press和v基于原始数据的范围:range(dat$press)和range(dat$v).我们不会超出此范围进行预测.但即使在这个范围内,你只有17个观测值.所以你仍然需要对情节持怀疑态度.
这是曲线:
二维曲线
这个玩具功能对于制作2D曲线很有用,v固定为某个级别:
curve_2D_fix_v <- function(model, v = 1, press_grid = seq(200, 480, by = 5), add = FALSE, col = "black") {
newdat <- data.frame(press = press_grid, v = v)
pred <- predict.glm(model, newdat, type = "response")
if (add) lines(press_grid, pred, col = col) else {
plot(press_grid, pred, xlab = "pressure", ylab = "predicted probability", type = "l", col = col, main = "logistic curve (2D)")
abline(h = c(0, 0.5, 1), lty = 2, col = col)
}
}
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如果add = FALSE,它打开一个新的绘图窗口; 虽然它是TRUE,它在前一个窗口上绘制(但是你有责任确保有这样一个窗口!)2D绘图提供了更多信息,因为你可以在0,0.5和1处添加一条水平线.
我们来吧:
curve_2D_fix_v(mylogit, v = 0.4, add = FALSE, col = "black")
curve_2D_fix_v(mylogit, v = 0.6, add = TRUE, col = "red")
curve_2D_fix_v(mylogit, v = 0.8, add = TRUE, col = "green")
curve_2D_fix_v(mylogit, v = 1, add = TRUE, col = "blue")
curve_2D_fix_v(mylogit, v = 1.2, add = TRUE, col = "cyan")
curve_2D_fix_v(mylogit, v = 0.4, add = TRUE, col = "yellow")
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这是曲线:
讨论
在这两个图中,我们看到gender(预测概率)和v(速度)之间的关系不是很强.在2D图中,几乎所有的值都v产生相同的曲线.另一方面,press(压力)是一种强烈的影响.
回到你的型号:
> summary(mylogit)
Coefficients:
Estimate Std. Error z value Pr(>|z|)
(Intercept) 8.08326 4.45463 1.815 0.0696 .
press -0.02575 0.01618 -1.591 0.1115
v -0.15385 4.83824 -0.032 0.9746
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
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你可以看到这v根本不重要!严格来说,press在0.1级也没有显着性.所以这是一个非常弱的模型.我建议你删除变量v并再次使用模型press作为唯一变量.