use*_*083 1 python tkinter python-3.x
如果用户从OptionMenu列表中选择一个选项,则应禁用该选项.
示例:如果用户选择"a",则应禁用选项"a",然后用户只能选择b或c.我尝试了下面的代码,但它返回错误,如图所示.我不想要menubutton.OptionMenu将服务于我的目的,但不是menubutton.
import tkinter as tk
from tkinter import *
class Disable_state(Frame):
def __init__(self, parent):
Frame.__init__(self, parent)
self.parent = parent
va = StringVar()
NAMES = { 'a' : 0, 'b' : 1, 'c' : 2 }
op = list(NAMES.keys())
self.menu = OptionMenu(self.parent, va, *op,command = lambda op: self.disable_option(op))
self.menu.grid(column=0, row=0)
def disable_option(self,op):
self.menu.config(op, state = "disabled")
if __name__ =="__main__":
root= Tk()
o = Disable_state(root)
root.mainloop()
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错误是
self.menu.config(op, state = "disabled")
File "C:\Python34\lib\tkinter\__init__.py", line 1319, in configure
return self._configure('configure', cnf, kw)
File "C:\Python34\lib\tkinter\__init__.py", line 1303, in _configure
cnf = _cnfmerge((cnf, kw))
File "C:\Python34\lib\tkinter\__init__.py", line 105, in _cnfmerge
cnf.update(c)
ValueError: dictionary update sequence element #0 has length 1; 2 is required
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似乎可以访问子窗口小部件menu,并且使用该entryconfigure方法可以禁用条目
self.menu['menu'].entryconfigure(op, state = "disabled")
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