Jackson XML到JSON转换器删除多个子记录

Question

我使用以下代码将我的源XML转换为JSON.但是,此代码会删除源XML中多次出现的子记录,并且输出JSON仅包含最后一个子记录.

如何将Jackson XML转换为JSON转换器以输出JSON中的所有子记录？

码

XmlMapper xmlMapper = new XmlMapper();
Map entries = xmlMapper.readValue(new File("source.xml"), LinkedHashMap.class);
ObjectMapper jsonMapper = new ObjectMapper();
String json = jsonMapper.writer().writeValueAsString(entries);
System.out.println(json);

源XML

<?xml version="1.0" encoding="ISO-8859-1"?>
<File>
  <NumLeases>1</NumLeases>
  <FLAG>SUCCESS</FLAG>
  <MESSAGE>Test Upload</MESSAGE>
  <Lease>
     <LeaseVersion>1</LeaseVersion>
     <F1501B>
        <NEDOCO>18738</NEDOCO>
        <NWUNIT>0004</NWUNIT>
        <NTRUSTRECORDKEY>12</NTRUSTRECORDKEY>
     </F1501B>
     <F1501B>
        <NEDOCO>18739</NEDOCO>
        <NWUNIT>0005</NWUNIT>
        <NTRUSTRECORDKEY>8</NTRUSTRECORDKEY>
     </F1501B>
  </Lease>
</File>

实际产出

{
  "NumLeases": "1",
  "FLAG": "SUCCESS",
  "MESSAGE": "Test Upload",
  "Lease": {
    "LeaseVersion": "1",
    "F1501B": {
      "NEDOCO": "18739",
      "NWUNIT": "0005",
      "NTRUSTRECORDKEY": "8"
    }
  }
}

预期产出

{
  "NumLeases": "1",
  "FLAG": "SUCCESS",
  "MESSAGE": "Test Upload",
  "Lease": {
    "LeaseVersion": "1",
    "F1501B": [
      {
        "NEDOCO": "18738",
        "NWUNIT": "0004",
        "NTRUSTRECORDKEY": "12"
      },
      {
        "NEDOCO": "18739",
        "NWUNIT": "0005",
        "NTRUSTRECORDKEY": "8"
      }
    ]
  }
}

任何帮助将不胜感激.谢谢!

Answer 1

我能够通过使用org.json API将源XML转换为JSONObject然后通过Jackson API 转换为JSON 来获得此问题的解决方案.

码

import java.io.File;
import java.io.FileInputStream;
import java.io.InputStream;

import org.apache.commons.io.IOUtils;
import org.json.JSONObject;
import org.json.XML;

import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializationFeature;

...
...

try (InputStream inputStream = new FileInputStream(new File(
                "source.xml"))) {
    String xml = IOUtils.toString(inputStream);
    JSONObject jObject = XML.toJSONObject(xml);
    ObjectMapper mapper = new ObjectMapper();
    mapper.enable(SerializationFeature.INDENT_OUTPUT);
    Object json = mapper.readValue(jObject.toString(), Object.class);
    String output = mapper.writeValueAsString(json);
    System.out.println(output);
}

...
...

源XML

<?xml version="1.0" encoding="ISO-8859-1"?>
<File>
  <NumLeases>1</NumLeases>
  <FLAG>SUCCESS</FLAG>
  <MESSAGE>Test Upload</MESSAGE>
  <Lease>
     <LeaseVersion>1</LeaseVersion>
     <F1501B>
        <NEDOCO>18738</NEDOCO>
        <NWUNIT>0004</NWUNIT>
        <NTRUSTRECORDKEY>12</NTRUSTRECORDKEY>
     </F1501B>
     <F1501B>
        <NEDOCO>18739</NEDOCO>
        <NWUNIT>0005</NWUNIT>
        <NTRUSTRECORDKEY>8</NTRUSTRECORDKEY>
     </F1501B>
  </Lease>
</File>

产量

{
  "File" : {
    "NumLeases" : "1",
    "FLAG" : "SUCCESS",
    "MESSAGE" : "Test Upload",
    "Lease" : {
      "LeaseVersion" : "1",
      "F1501B" : [ {
        "NEDOCO" : "18738",
        "NWUNIT" : "0004",
        "NTRUSTRECORDKEY" : "12"
      }, {
        "NEDOCO" : "18739",
        "NWUNIT" : "0005",
        "NTRUSTRECORDKEY" : "8"
      } ]
    }
  }
}