Ang*_*gel 0 polymorphism traits rust
我正在学习Rust,我在实现多态方面遇到了困难.我想用数组来存储Circle或者Test.
trait Poli {
fn area(&self) -> f64;
}
struct Circle {
x: f64,
y: f64,
radius: f64,
}
impl Circle {
fn new (xx: f64, yy: f64, r: f64) -> Circle{
Circle{ x: xx, y: yy, radius: r }
}
}
impl Poli for Circle {
fn area(&self) -> f64 {
std::f64::consts::PI * (self.radius * self.radius)
}
}
struct Test {
x: f64,
y: f64,
radius: f64,
test: f64,
}
impl Test {
fn new (xx: f64, yy: f64, r: f64, t: f64) -> Circle{
Test{ x: xx, y: yy, radius: r, test: t, }
}
}
impl Poli for Test {
fn area(&self) -> f64 {
std::f64::consts::PI * (self.radius * self.radius)
}
}
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我不知道如何使用相同的存储类型的向量trait:
let cir = Circle::new(10f64, 10f64, 10f64);
let test = Test::new(10f64, 10f64, 10f64, 10f64);
//let mut vec: Vec<Poli> = Vec::new(); <---
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我想迭代向量并从特征中调用函数.有没有办法做到这一点,或者一些替代方案?
我读了特征对象文档,但我认为这不是我想要的.
正如您链接到的页面中所提到的,您需要将Poli实现结构存储为Vec<&Poli>或Vec<Box<Poli>>依赖于您是否要拥有值或仅存储引用:
// Owned
let circle = Circle::new(10f64, 10f64, 10f64);
let test = Test::new(10f64, 10f64, 10f64, 10f64);
let polis = vec![Box::new(circle) as Box<Poli>, Box::new(test) as Box<Poli>];
for poli in polis {
println!("{}", poli.area());
}
// Reference
let circle = Circle::new(10f64, 10f64, 10f64);
let test = Test::new(10f64, 10f64, 10f64, 10f64);
let polis = vec![&circle as &Poli, &test as &Poli];
for poli in polis {
println!("{}", poli.area());
}
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产量
314.1592653589793
314.1592653589793
314.1592653589793
314.1592653589793
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