根据条件连接两个表以及第二个表中的记录数

Gim*_*ali 5 mysql sql database join

我有以下表格 -

这是SQLFIDDLE

类别

+-----------+-------------+
|  column   |    type     |
+-----------+-------------+
| id        | int(11)     |
| name      | varchar(40) |
| unit      | varchar(50) |
| is_active | tinyint(1)  |
+-----------+-------------+
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制品

+-------------+---------------+
|   column    |     type      |
+-------------+---------------+
| id          | int(11)       |
| category_id | int(11)       |
| name        | varchar(40)   |
| base_rate   | decimal(10,2) |
| is_active   | tinyint(1)    |
+-------------+---------------+
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我想获得类别列表以及活跃的产品数量.如果某个类别的产品没有活动,则应返回0.

有点像下表 -

+----+--------+--------------+
| id |  name  | active_count |
+----+--------+--------------+
|  1 | Steel  |            1 |
|  2 | Cement |            2 |
+----+--------+--------------+
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我想出了以下查询 -

SELECT c.id, c.name, c.unit, COUNT(p.category_id) as active_count 
FROM `categories` c 
JOIN `products` p
    ON c.id = p.category_id
WHERE ( p.is_active = 1 )
GROUP BY p.category_id;
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只有当每个类别中至少有一个产品处于活动状态时,上述查询才有效.如果没有产品面世,它应该返回active_count0

我怎样才能解决这个问题 ?

这是SQLFIDDLE

Gio*_*sos 6

使用LEFT JOIN而不是INNER JOIN:

SELECT c.id, c.name, c.unit, COUNT(p.category_id) as active_count 
FROM `categories` c 
LEFT JOIN `products` p
    ON c.id = p.category_id AND p.is_active = 1 
GROUP BY c.id;
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将谓词p.is_active = 1WHERE子句移动到也很重要ON,以便查询返回表的所有记录categories.