lme*_*yew 2 delphi multithreading delphi-2010
我是delphi 2010的用户,我目前的机器是intel core i7,运行windows 7 x64.我写了以下代码:
type
TForm1 = class(TForm)
Memo1: TMemo;
Button1: TButton;
Button2: TButton;
procedure Button1Click(Sender: TObject);
procedure Button2Click(Sender: TObject);
private
FCount: Integer;
FTickCount: Cardinal;
procedure DoTest;
procedure OnTerminate(Sender: TObject);
end;
TMyThread = class(TThread)
private
FMethod: TProc;
protected
procedure Execute; override;
public
constructor Create(const aCreateSuspended: Boolean; const aMethod: TProc);
end;
var
Form1: TForm1;
implementation
{$R *.dfm}
procedure TForm1.Button1Click(Sender: TObject);
var i: integer;
T1, T2: Cardinal;
begin
T1 := GetTickCount;
for i := 0 to 9 do
DoTest;
T2 := GetTickCount;
Memo1.Lines.Add(Format('no thread=%4f', [(T2 - T1)/1000]));
end;
procedure TForm1.Button2Click(Sender: TObject);
var T: TMyThread;
i: integer;
begin
FCount := 0;
FTickCount := GetTickCount;
for i := 0 to 9 do begin
T := TMyThread.Create(True, DoTest);
T.OnTerminate := OnTerminate;
T.Priority := tpTimeCritical;
if SetThreadAffinityMask(T.Handle, 1 shl (i mod 8)) = 0 then
raise Exception.Create(IntToStr(GetLastError));
Inc(FCount);
T.Start;
end;
end;
procedure TForm1.DoTest;
var i: integer;
begin
for i := 1 to 10000000 do
IntToStr(i);
end;
procedure TForm1.OnTerminate(Sender: TObject);
begin
Dec(FCount);
if FCount = 0 then
Memo1.Lines.Add(Format('thread=%4f', [(GetTickCount - FTickCount)/1000]));
end;
constructor TMyThread.Create(const aCreateSuspended: Boolean; const aMethod:
TProc);
begin
inherited Create(aCreateSuspended);
FMethod := aMethod;
FreeOnTerminate := True;
end;
procedure TMyThread.Execute;
begin
FMethod;
end;
Run Code Online (Sandbox Code Playgroud)
单击Button1将显示12.25秒,而Button2将显示12.14秒.我的问题是为什么我不能得到更明显的时间差(不到10秒)虽然我正在运行并行线程?
内存分配似乎是这里的主要问题.
如果您用有效载荷替换
procedure TForm6.DoTest;
var i: integer;
a: double;
begin
a := 0;
for i := 1 to 10000000 do
a := Cos(a);
end;
Run Code Online (Sandbox Code Playgroud)
代码将很好地并行化,表明您的框架没有真正的问题.
但是,如果您使用内存分配/取消分配替换有效内容
procedure TForm6.DoTest;
var i: integer;
p: pointer;
begin
for i := 1 to 10000000 do begin
GetMem(p, 10);
FreeMem(p);
end;
end;
Run Code Online (Sandbox Code Playgroud)
并行版本的运行速度比单线程版本慢得多.
调用IntToStr时,会分配和销毁临时字符串,并且此分配/解除分配正在创建瓶颈.
BTW1:除非你真的知道你在做什么,否则我强烈建议不要在tpTimeCritical优先级上运行线程.即使你真的真的知道自己在做什么,也不应该这样做.
BTW2:除非你真的知道你在做什么,否则你不应该在线程级别上混淆亲和力掩码.系统非常智能,可以很好地安排线程.
| 归档时间: |
|
| 查看次数: |
1897 次 |
| 最近记录: |