TABLE_A
column name: list_id
record 1: 1,2,5,6,8
record 2: 1,3,2
record 3: 6,7,2
record 4: 9,8,0
表-B
id ='2';
如何选择id='2'逗号分隔字符串中的记录?从上面的例子中,它应该返回记录1,2和3.
查询(如何修改此查询?):
SELECT * FROM Table_a,Table_b WHERE Table_b.id = Table_a.list_id;
使用 find_in_set 函数,但这不是您应该标准化数据的优化方式。
SELECT * FROM 
Table_a AS a 
JOIN Table_b AS b ON FIND_IN_SET(b.id,a.list_id)