Laravel 获取用户今天和明天的生日

ssu*_*hat 4 php laravel

我有这个查询来获取明天和今天的生日用户:

$birthday[Carbon::now()->format('Y-m-d')] = User::whereRaw("DATE_FORMAT(birthday, '%m-%d') = DATE_FORMAT(now(),'%m-%d')")
        ->orWhereRaw("DATE_FORMAT(birthday,'%m-%d') = '02-29' and DATE_FORMAT(birthday, '%m') = '02' AND 
        LAST_DAY(NOW()) = DATE(NOW())")
        ->selectRaw('first_name, last_name, email, birthday')
        ->get();

$birthday[Carbon::now()->addDay()->format('Y-m-d')] = User::whereRaw("DATE_FORMAT(birthday, '%m-%d') = DATE_FORMAT(NOW() + INTERVAL 1 DAY, '%m-%d')")
        ->orWhereRaw("DATE_FORMAT(birthday,'%m-%d') = '02-29' and DATE_FORMAT(birthday, '%m') = '02' AND 
            LAST_DAY(NOW()) = DATE(NOW())")
        ->selectRaw('first_name, last_name, email, birthday')
        ->get();

 return $birthday;
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查询会给我这个结果:

{
    "2016-03-30": [
        {
          "first_name": "Harmon",
          "last_name": "Olson",
          "email": "GleasonSwaniawski.Jeanne@yahoo.com",
          "birthday": "1990-03-30"
        },
        {
          "first_name": "John",
          "last_name": "Doe",
          "email": "john.doe@yahoo.com",
          "birthday": "1990-03-30"
        },
    ],
    "2016-03-31": [
        {
          "first_name": "User10",
          "last_name": null,
          "email": "user10@user.com",
          "birthday": "1990-03-31"
        }
    ]
}
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当然它工作正常并且结果正是我想要的,但我认为我的查询可以缩短(将查询合并为一个)以获得我想要的结果。

有什么建议如何缩短它吗?

提前致谢!

Dev*_*ddy 10

为了今天的生日使用

User::whereMonth('birth_date', Carbon::now()->format('m'))
->whereDay('birth_date', Carbon::now()->format('d'))
->get();
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还有明天的生日

User::whereMonth('birth_date', Carbon::now()->format('m'))
->whereDay('birth_date', Carbon::now()->addDay()->format('d'))
->get();
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注意:-birth_date列日期格式为表中的yyyy-mm-dd数据类型date