圆环图python

Question

所以我使用这段代码用 python 创建了一个甜甜圈图（灵感来自这个甜甜圈图配方）：

def make_pie(sizes, text,colors,labels):
    import matplotlib.pyplot as plt
    import numpy as np

    col = [[i/255. for i in c] for c in colors]

    fig, ax = plt.subplots()
    ax.axis('equal')
    width = 0.35
    kwargs = dict(colors=col, startangle=180)
    outside, _ = ax.pie(sizes, radius=1, pctdistance=1-width/2,labels=labels,**kwargs)
    plt.setp( outside, width=width, edgecolor='white')

    kwargs = dict(size=20, fontweight='bold', va='center')
    ax.text(0, 0, text, ha='center', **kwargs)
    plt.show()

c1 = (226,33,7)
c2 = (60,121,189)

make_pie([257,90], "Gender (AR)",[c1,c2],['M','F'])

这导致：

我的问题是现在我想要相应的百分比。为此，我只是添加了论点：

autopct='%1.1f%%'

像这样：

kwargs = dict(colors=col, startangle=180,autopct='%1.1f%%')

但这会导致以下错误：

Traceback (most recent call last):
  File "draw.py", line 30, in <module>
    make_pie([257,90], "Gender (AR)",[c1,c2],['M','F'])
  File "draw.py", line 13, in make_pie
    outside, _ = ax.pie(sizes, radius=1, pctdistance=1-width/2,labels=labels,**kwargs)
ValueError: too many values to unpack

那么，我做错了什么？

Answer 1

从文档字符串：

If *autopct* is not *None*, return the tuple (*patches*,
  *texts*, *autotexts*), where *patches* and *texts* are as
  above, and *autotexts* is a list of
  :class:`~matplotlib.text.Text` instances for the numeric
  labels.

所以，如果你想解开的结果，pie()使用autopct你需要3个值：

kwargs = dict(colors=col, startangle=180, autopct='%1.1f%%')
outside, _, _ = ax.pie(sizes, radius=1, pctdistance=1-width/2,
                       labels=labels,**kwargs)

或者，如果不拆包它会更健壮，因此无论是否使用它都可以使用autopct：

outside = ax.pie(sizes, radius=1, pctdistance=1-width/2,
                 labels=labels,**kwargs)[0]