是否有任何技术可以允许这样的行设置
WITH
base AS
(
SELECT 1 N FROM DUAL UNION ALL
SELECT 2 N FROM DUAL UNION ALL
SELECT 3 N FROM DUAL UNION ALL
SELECT 6 N FROM DUAL UNION ALL
SELECT 7 N FROM DUAL UNION ALL
SELECT 17 N FROM DUAL UNION ALL
SELECT 18 N FROM DUAL UNION ALL
SELECT 19 N FROM DUAL UNION ALL
SELECT 21 N FROM DUAL
)
SELECT a.N
FROM base a
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产生结果
1 3
6 7
17 19
21 21
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它实际上是行到范围操作.我正在使用Oracle Land,并会感激任何建议.
我觉得这可能会改进,但它有效:
WITH base AS (
SELECT 1 N FROM DUAL UNION ALL
SELECT 2 N FROM DUAL UNION ALL
SELECT 3 N FROM DUAL UNION ALL
SELECT 6 N FROM DUAL UNION ALL
SELECT 7 N FROM DUAL UNION ALL
SELECT 17 N FROM DUAL UNION ALL
SELECT 18 N FROM DUAL UNION ALL
SELECT 19 N FROM DUAL UNION ALL
SELECT 21 N FROM DUAL
)
, lagged AS
(
SELECT n, LAG(n) OVER (ORDER BY n) lag_n FROM base
)
, groups AS
(
SELECT n, row_number() OVER (ORDER BY n) groupnum
FROM lagged
WHERE lag_n IS NULL OR lag_n < n-1
)
, grouped AS
(
SELECT n, (SELECT MAX(groupnum) FROM groups
WHERE groups.n <= base.n
) groupnum
FROM base
)
SELECT groupnum, MIN(n), MAX(n)
FROM grouped
GROUP BY groupnum
ORDER BY groupnum
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