Ego*_*gor 4 sql sql-server sql-server-2008
我有一个表变量@searchResult:
DECLARE @searchResult TABLE (
[name_template] NVARCHAR(50),
[record_id] INT,
[record_name] NVARCHAR(50)
);
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和表[records]:
CREATE TABLE [records] (
[record_id] INT IDENTITY(1, 1) PRIMARY KEY,
[record_name] NVARCHAR(50)
)
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@searchResult只包含[name_template]填充的记录。我想与最新的更新它[record_id],并[record_name]从[records]表匹配[name_template]。
我试过以下 SQL 查询但没有成功:
UPDATE @searchResult
SET [record_id] = r.[record_id], [record_name] = r.[record_name]
FROM (
SELECT TOP 1
r.[record_id]
, r.[record_name]
FROM [records] AS r
WHERE r.[record_name] LIKE [name_template]
ORDER BY r.[record_id] DESC
) AS r;
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错误信息:
无效的列名“name_template”。
@searchResult使用所需值更新的正确语法是什么?
你需要CROSS APPLY在桌子上做一个。
UPDATE @searchResult
SET [record_id] = r.[record_id],
[record_name] = r.[record_name]
FROM @searchResult SR
CROSS APPLY (
SELECT TOP 1 *
FROM [records]
WHERE [record_name] LIKE [name_template] -- Your wish, but do you really need LIKE matching??
ORDER BY [record_id] DESC
) AS r;
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