这很奇怪:使用groovy字符串来保存一些命令行来执行,我发现有时如果字符串中有引号字符,执行只是默默地失败.
WTF?(更新,见下文.)
这是我的测试程序:
print " 1: " ; "grep nameserver /etc/resolv.conf".execute().text.eachLine {println it } ; println ""
print " 2: " ; "grep 'nameserver' /etc/resolv.conf".execute().text.eachLine {println it } ; println ""
print " 3: " ; """grep nameserver /etc/resolv.conf""".execute().text.eachLine {println it } ; println ""
print " 4: " ; """grep "nameserver" /etc/resolv.conf""".execute().text.eachLine {println it } ; println ""
print " 5: " ; """grep 'nameserver' /etc/resolv.conf""".execute().text.eachLine {println it } ; println ""
print " 6: " ; "awk /nameserver/ /etc/resolv.conf".execute().text.eachLine{ println it } ; println ""
print " 7: " ; "awk '/nameserver/' /etc/resolv.conf".execute().text.eachLine{ println it } ; println ""
print " 8: " ; """awk "/nameserver/" /etc/resolv.conf""".execute().text.eachLine{ println it } ; println ""
print " 9: " ; """awk '/nameserver/' /etc/resolv.conf""".execute().text.eachLine{ println it } ; println ""
print "10: " ; """awk "/nameserver/{print \$2}" /etc/resolv.conf""".execute().text.eachLine{ println it } ; println ""
return
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结果如下:
$ groovy weird.groovy
1: nameserver 10.3.0.101
nameserver 10.4.1.237
nameserver 10.2.1.34
2:
3: nameserver 10.3.0.101
nameserver 10.4.1.237
nameserver 10.2.1.34
4:
5:
6: nameserver 10.3.0.101
nameserver 10.4.1.237
nameserver 10.2.1.34
7:
8: nameserver 10.3.0.101
nameserver 10.4.1.237
nameserver 10.2.1.34
domain lnx.copansys.com
search lnx.copansys.com tst.copansys.com copansys.com
9:
10:
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更新
这是另一个例子:
"bash -c echo Hello".execute().text.eachLine{ println it }
"bash -c echo 'Hello'".execute().text.eachLine{ println it }
"bash -c echo \'Hello\'".execute().text.eachLine{ println it }
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结果:
groovy> "bash -c echo Hello".execute().text.eachLine{ println it }
groovy> "bash -c echo 'Hello'".execute().text.eachLine{ println it }
groovy> "bash -c echo \'Hello\'".execute().text.eachLine{ println it }
'Hello!'
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观察嵌入反斜杠引用'似乎没有帮助.
ata*_*lor 11
使用命令执行命令时String.execute(),它们不会被命令shell解析.引号传递给执行的实际命令; 在这种情况下,grep和awk.
通过用echo替换grep和awk来说明这一点:
print " 1: " ; "echo something".execute().text.eachLine {println it } ; println ""
print " 2: " ; "echo 'something'".execute().text.eachLine {println it } ; println ""
print " 3: " ; """echo something""".execute().text.eachLine {println it } ; println ""
print " 4: " ; """echo "something" """.execute().text.eachLine {println it } ; println ""
print " 5: " ; """echo 'something'""".execute().text.eachLine {println it } ; println ""
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结果如下:
1: something
2: 'something'
3: something
4: "something"
5: 'something'
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一个简单的解决方法是将命令行构建为字符串列表:
["awk", 'BEGIN { print "hello" }'].execute().text
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如果您需要更好地控制解析命令的方式,那么请看一下ProcessBuilder,Java类String.execute()是围绕它构建的.
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