function holiday_hitlist($tablename, $hit_user){
global $host, $user, $pass, $dbname;
$link = mysql_connect($host, $user, $pass, $dbname);
print "<div class=\"hit_list\">
<h3>My Holiday Hitlist</h3>
<p>Five things I want the most, based on my desirability ratings.<br/>You can't go wrong with this stuff!</p>
<ol>";
$sql = "SELECT title, URL, price FROM $dbname.$tablename WHERE user='$hit_user' AND rank >= 3 ORDER BY date DESC LIMIT 5";
$result = mysql_query($sql) or die ("Couldn't retrieve holiday hit list for this user. " . mysql_error());
while($row = mysql_fetch_array($result)) {
$title = $row['title'];
$url = $row['URL'];
$price = "$" . $row['price'];
$output = print "<li><a href=\"$url\" target=\"_blank\">$title</a> $price</li>";
}
print "</ol></div>";
return $output;
}
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在HTML页面上,它将"1"紧跟在结束div标记之后.为什么?
看到这条线
$output = print "<li><a href=\"$url\" target=\"_blank\">$title</a> $price</li>";
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您应该在$ output =之后删除打印件
或者你可能只需要删除$ output =
我不太清楚你的意图.
要解释一下,$ output正在获得print"..."的返回值
来自php.net参考:
"回归价值观
总是返回1."
http://ca.php.net/manual/en/function.print.php
您应该将$ output指定为您想要的输出,然后使用print来显示该输出.
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