Fre*_*ind 20 python sqlalchemy
我现在知道如何查询模型.假设有一个Question模型:
class Question(Base):
__tablename__ = "questions"
id=Column(...)
user_id=Column(...)
...
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现在,我可以这样做:
question = Session.query(Question).filter_by(user_id=123).one()
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但是,现在,我有一张桌子(不是模特)questions:
questions = Table('questions', Base.metadata,
Column(id, ...),
Column(user_id, ...),
....)
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如何查询它作为我对模型的处理?
Session.query(questions).filter_by(user_id=123).one()
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这将报告错误:
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "E:\Python27\lib\site-packages\sqlalchemy-0.6.3-py2.7.egg\sqlalchemy\orm\query.py", line 851, in filter_by
for key, value in kwargs.iteritems()]
File "E:\Python27\lib\site-packages\sqlalchemy-0.6.3-py2.7.egg\sqlalchemy\orm\util.py", line 567, in _entity_descriptor
desc = entity.class_manager[key]
AttributeError: 'NoneType' object has no attribute 'class_manager'
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但:
Session.query(questions).all()
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没关系
难道filter_by只为模型的工作?我怎样才能查询表格?
Joc*_*zel 28
我想这是 Session.query(questions).filter(questions.c.user_id==123).one()