将字符串拆分为Dictionary键和Value

Question

我试图将从相机收到的响应(字符串)拆分为键和值.这是来自IP摄像头的字符串:

{"error":0,"session":678939290,"group":131071}

我想将它们分成没有""的键和数组.例如:

键 <----> 值

错误 0

会议 678939290

第 131071 组

以下是我目前使用的代码:

string tempResponse = serverResponse;


        //Remove Left and Right curly braces
        tempResponse = tempResponse.Replace("{", "");
        tempResponse = tempResponse.Replace("}", "");

        //Remove '"' from the string
        tempResponse = tempResponse.Replace("\"", "");

        //Now Make sure that there is no Space begining and end of the string
        tempResponse = tempResponse.TrimStart().TrimEnd();


        var items = tempResponse.Split(new[] { ',' }, StringSplitOptions.None)
    .Select(s => s.Split(new[] { ':' }));

        Dictionary<string, string> camInfoDICT = null; //Stores the camInfo as keys and values
        camInfoDICT = new Dictionary<string, string>();
        foreach (var item in items)
        {
            try
            {
                camInfoDICT.Add(item[0], item[1]);
            }
            catch (Exception e)
            {
                Debug.Log("Exception " + e.Message);
            }
        }

它有效.该代码的功能如预期,我能提取从信息camInfoDICT的钥匙和价值观.

该问题是,它抛出一个Exception的Exception Array index is out of range.在

 foreach (var item in items)
            {
                try
                {
                    camInfoDICT.Add(item[0], item[1]);
                }
                catch (Exception e)
                {
                    Debug.Log("Exception " + e.Message);
                }
            }

我哪里做错了？

Answer 1

而不是手动解析,使用Json转换.该字符串是一个JSON字符串.您可以使用任何可用的JSON反序列化器,例如使用Newtonsoft JSON解析器,它将是:

string jsonString = "{\"error\":0,\"session\":678939290,\"group\":131071}";
Dictionary<string, int> camInfoDICT = JsonConvert.DeserializeObject<Dictionary<string, int>>(jsonString);

要包含Netwonsoft JSON,请在Visual Studio中使用Nugget Package Manager.