在javascript中将对象从星期日到星期六排序

Question

大家好我知道这个问题有几次被问到,但我没有得到我的问题的确切答案.

// I have array of object like this
data=[
        // "sunday": 1, // << sunday is first day of week      
      {DayOfWeek:"Saturday", TotalCount:30},
      {DayOfWeek:"Friday", TotalCount:10},
      {DayOfWeek:"Monday", TotalCount:23},
      {DayOfWeek:"Sunday", TotalCount:18}, 
      {DayOfWeek:"Wednesday", TotalCount:20}        
    ];


// I need sorted like this:
data=[
        // "sunday": 1, // << sunday is first day of week
      {DayOfWeek:"Sunday", TotalCount:18},  
      {DayOfWeek:"Monday", TotalCount:23},
      {DayOfWeek:"Wednesday", TotalCount:20},
      {DayOfWeek:"Friday", TotalCount:10},
      {DayOfWeek:"Saturday", TotalCount:30}  
    ];

我试过这个,但我能够得到预期的结果.它是通过satring字母表给出mi排序的数组

星期五星期六.

var sorter = {//"sunday":1,//"星期日是星期几的第一天"星期日":1,"星期一":2,"星期二":3,"星期三":4,"星期四": 5,"星期五":6,"星期六":7}

  var result= data.sort(function sortByDay(a, b) {
    var day1 = a.DayOfWeek.toLowerCase();
    var day2 = b.DayOfWeek.toLowerCase();
    return sorter[day1] > sorter[day2];
  });

请帮帮我,提前致谢

Answer 1

您可以使用订单的对象对其进行排序,就像您已经拥有的那样,但是您需要区别

return order[a.DayOfWeek] - order[b.DayOfWeek];

作为排序回调的返回值.

var data = [{ DayOfWeek: "Saturday", TotalCount: 30 }, { DayOfWeek: "Friday", TotalCount: 10 }, { DayOfWeek: "Monday", TotalCount: 23 }, { DayOfWeek: "Sunday", TotalCount: 18 }, { DayOfWeek: "Wednesday", TotalCount: 20 }],
    order = { Sunday: 1, Monday: 2, Tuesday: 3, Wednesday: 4, Thursday: 5, Friday: 6, Saturday: 7 };

data.sort(function (a, b) {
    return order[a.DayOfWeek] - order[b.DayOfWeek];
});
document.write('<pre>' + JSON.stringify(data, 0, 4) + '</pre>');

Answer 2

没有任何内置函数，但解决方案应该不会太难。下面是一个例子：

function s(a,b){
    return daysOfWeek.indexOf(a) - daysOfWeek.indexOf(b); // basic sort function that compares the indexes of the two days
}
var inputArray = ["Saturday", "Monday", "Sunday", "Tuesday"]; // input
var daysOfWeek = ["Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday"]; // array of days sorted
console.log(inputArray.sort(s)); // output