Python:从路径中提取文件夹名称

Vin*_*oft 1 python path

我在python中有一个作为字符串的路径:

path = "/folder_a/folder_b/folder_c/folder_d"
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如何从path.

Mik*_*ler 6

您可以使用os.path.basename

>>> path = "/folder_a/folder_b/folder_c/folder_d"
>>> import os
>>> os.path.basename(path)
'folder_d'
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