Imr*_*ran 19 mongodb mongodb-query
我是mongo的新手,并且与下面的人进行了艰苦的斗争.我有2个收集结构如下.对于我的生活,我无法弄清楚如何对学校集合进行$ lookup.阅读其他帖子,我肯定使用ObjectId作为参考以及外国字段.
以下是我的结构:
校友:
{
"_id": "john",
"items": [
{
"name": "John",
"items": [
{
"school": ObjectId("56de35ab520fc05b2fa3d5e4"),
"grad": true
},
{
"school": ObjectId("56de35ab520fc05b2fa00000"),
"grad": false
}
]
},
{
"name": "Johnny"
// notice no nested items, this doc should still be included in result
},
{
"name": "Jon",
"items": [
{
"school": ObjectId("56de35ab520fc05b2fa11111"),
"grad": false
}
]
}
]
}
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学校
{
_id: ObjectId("56de35ab520fc05b2fa3d5e4"),
name: "Some University",
street: "ABC Boulevard"
}
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我想要得到的:
{
"_id": "john",
"items": [
{
"name": "John",
"items": [
{
"school": ObjectId("56de35ab520fc05b2fa3d5e4"),
"grad": true,
"schoolInfo": {
_id: ObjectId("56de35ab520fc05b2fa3d5e4"),
name: "Some University",
street: "ABC Boulevard"
}
},
{
"school": ObjectId("56de35ab520fc05b2fa00000"),
"grad": true,
"schoolInfo": {
_id: ObjectId("56de35ab520fc05b2fa00000"),
name: "Another University",
street: "123 Boulevard"
}
}
]
},
{
name: "Johnny"
},
{
"name": "Jon",
"items": [
{
"school": ObjectId("56de35ab520fc05b2fa11111"),
"grad": true,
"schoolInfo": {
_id: ObjectId("56de35ab520fc05b2fa11111"),
name: "Some University",
street: "ABC Boulevard"
}
}
]
}
]
}
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我试过的查询无济于事:
db.alumni.aggregate([
{$match: {_id: 'john'}},
{$lookup: {
from: 'schools',
localField: 'items.items.school',
foreignField: '_id',
as: 'schoolInfo'}}
])
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任何帮助将不胜感激!
pro*_*r79 32
在这种情况下,需要在聚合框架中使用$ unwind和$ project
请看下面:
db.alumni.aggregate([
{$match: {_id: 'john'}},
{$unwind:"$items"},
{$unwind:"$items.items"},
{$lookup: {
from: 'schools',
localField: 'items.items.school',
foreignField: '_id',
as: 'schoolInfo'}},
{$unwind:"$schoolInfo"},
{$project:{
"_id":1,
"items":[{
"name":"$items.name",
"items":[{
"school":"$schoolInfo._id" ,
"grad":"$items.items.grad" ,
"schoolInfo":"$schoolInfo"
}]
}]
}}
]).pretty()
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看看它是如何工作的 - 尝试从查询中删除聚合阶段并检查文档结构.
这样可以更好地处理$items.items阵列中的多个学校吗?
db.alumni.aggregate([
{$match: {_id: 'john'}},
{$unwind:"$items"},
{$unwind:"$items.items"},
{$lookup: {
from: 'schools',
localField: 'items.items.school',
foreignField: '_id',
as: 'schoolInfo'}},
{$unwind:"$schoolInfo"},
{$group:{
_id: {
_id: '$_id',
name: '$items.name',
},
items: {
$push: {
'grad': '$items.items.grad',
'school': '$schoolInfo._id'
'schoolInfo': '$schoolInfo'
}
}
}},
{$group:{
_id: '$_id._id',
items: {
$push: {
'name': '$_id.name',
'items': '$items'
}
}
}}
]).pretty()
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我没有解决丢失的情况,$items.items但是您可以查看$ unwind空数组
另外,最好是在没有条目的情况下保留一个空数组而不是什么,即
{
name: "Johnny",
items: [],
},
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