如何处理来自Search Manager的回调？

Question

我们假设如下:

Activity A calls Search Manager
User searches, and search results are displayed in Activity B
User clicks on a list item in Activity B 
App switches back to Activity A

我无法处理从活动B到活动A的回调,因为我没有搜索管理器意图(我认为？).

呼叫搜索管理器(在活动A中)

public boolean onOptionsItemSelected(MenuItem item) {
        // Handle item selection
        switch (item.getItemId()) {
        case R.id.add_symbol:
            onSearchRequested(); //result of search will show Activity B
            return true;
        default:
            return super.onOptionsItemSelected(item);
        }
    }

用户选择列表项后返回活动A.

listView.setOnItemClickListener(new OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> a, View v, int position, long id) {
                Quote myQuote = new Quote();
                myQuote.name = (companies.get(position).name);
                myQuote.symbol = (companies.get(position).symbol);

                //TODO: add new quote to master quote list in Main
                //TODO: serialize in Main
                //TODO: go back to last activity

                Intent myIntent = new Intent(getApplicationContext(), Main.class);
                startActivityForResult(myIntent, PICK_COMPANY_REQUEST);
            }
        });

在活动A中处理回调:

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        if (requestCode == PICK_COMPANY_REQUEST) {
            if (resultCode == RESULT_OK) {
                Toast toast = Toast.makeText(getApplicationContext(), "Stock added", Toast.LENGTH_SHORT);
                toast.show();
            }
        }
    }

将PICK_COMPANY_REQUEST永远不会被发送到呼叫回来.为什么是这样？我假设因为搜索管理器具有意图,而不是活动B.我如何确保调用它？

永远不会调用onActivityResult().为什么？

Answer 1

我发布了一个答案,我认为在Android onSearchRequested()回调调用活动时遇到了同样的问题

Skythe是正确的,onActivityResult因为活动A没有为结果启动搜索活动.

为了解决这个问题,我将Activity A定义为可搜索的actvity(在清单中),以便它接收搜索意图,然后手动启动Activity B startActivityForResult,传入查询并让Activity B正常处理搜索.

您可以在上面的链接中看到我的回复,或者我在此博文中有更详细的说明.