提升权限不适用于UseShellExecute = false

Question

我想启动一个具有提升权限但具有隐藏窗口的子进程(实际上是相同的控制台应用程序).

我做下一个:

var info = new ProcessStartInfo(Assembly.GetEntryAssembly().Location)
{
    UseShellExecute = true, // !
    Verb = "runas", 
};

var process = new Process
{
    StartInfo = info
};

process.Start();

这工作:

var identity = new WindowsPrincipal(WindowsIdentity.GetCurrent());
identity.IsInRole(WindowsBuiltInRole.Administrator); // returns true

但是UseShellExecute = true创建了一个新窗口,我也无法重定向输出.

所以我下次做的时候:

var info = new ProcessStartInfo(Assembly.GetEntryAssembly().Location)
{
    RedirectStandardError = true,
    RedirectStandardOutput = true,
    UseShellExecute = false, // !
    Verb = "runas"
};

var process = new Process
{
    EnableRaisingEvents = true,
    StartInfo = info
};

DataReceivedEventHandler actionWrite = (sender, e) =>
{
    Console.WriteLine(e.Data);
};

process.ErrorDataReceived += actionWrite;
process.OutputDataReceived += actionWrite;

process.Start();
process.BeginOutputReadLine();
process.BeginErrorReadLine();
process.WaitForExit();

这不会提升权限,上面的代码返回false.为什么？？

Answer 1

只有在ShellExecuteEx()启动进程时,ProcessStartInfo.Verb才会生效.这需要UseShellExecute = true.重定向I/O并隐藏窗口只能在CreateProcess()启动进程时才能工作.这需要UseShellExecute = false.

好吧,这就是为什么它不起作用.不确定是否禁止启动绕过UAC的隐藏进程是故意的.大概. 很可能.

检查此Q + A以获取显示UAC提升提示所需的清单.

Answer 2

在我的情况下,一旦提升的子进程完成就可以获得输出.这是我提出的解决方案.它使用临时文件:

var output = Path.GetTempFileName();
var process = Process.Start(new ProcessStartInfo
{
    FileName = "cmd",
    Arguments = "/c echo I'm an admin > " + output, // redirect to temp file
    Verb = "runas", // UAC prompt
    UseShellExecute = true,
});
process.WaitForExit();
string res = File.ReadAllText(output);
// do something with the output
File.Delete(output);