基本上可以通过以下方式进行排序:
Collections.sort(列表);
但我的情况有点不同.我有一个包含以下对象的List.
示例代码1:
public class GetTraders {
private String getTraderLegalName;
private String businessName;
private Object status;
public GetTraders(String getTraderLegalName, String businessName, String status) {
this.getTraderLegalName=getTraderLegalName;
this.businessName=businessName;
this.status=status;
}
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我有一个课程,它将为以上列表提供如下价值:
public Class getResult {
List<GetTraders> traders=new ArrayList<GetTraders>();
public void valueGivenByuser(String legal,String business,Object status)throws Exception {
GetTraders trade=new GetTraders(legal,business,status);
traders.add(trade); //Adding value to arrayList
}
}
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这里的问题是,一旦我在交易者arraylist中添加了所有值,我需要排序并显示为输出.我尝试使用collections.sort()但它显示了编译器异常.
如果仔细查看Collections API,您会看到有两种选择:
1)让你的GetTraders类实现Comparable接口并调用
public static <T extends Comparable<? super T>> void sort(List<T> list)
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2)为GetTraders类创建一个新的Comparator并调用
public static <T> void sort(List<T> list, Comparator<? super T> c)
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第一个解决方案是最简单的解决方案,但如果您需要根据多个条件对GetTraders对象进行排序,那么第二个解决方案是最佳选择.
正如@Vaseph所指出的,如果你使用的是Java 8,生活会变得更加容易,因为你需要做的就是:
traders.sort((GetTraders trade1, GetTraders trade2) -> {
return trade1.getBusinessName().compareTo(trade2.getBusinessName());
});
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但是如果您遇到Comparable和Comparator接口的麻烦,我建议您先进入Java-8之前的解决方案,然后再进入功能接口的神奇世界.
为了完整起见,请在下面找到每个解决方案的示例:
1)基于可比的解决方案:
import java.util.ArrayList;
import java.util.Collections;
import java.util.List;
public class GetTraders1 implements Comparable<GetTraders1> {
private String getTraderLegalName;
private String businessName;
private Object status;
public GetTraders1(String getTraderLegalName, String businessName, String status) {
this.getTraderLegalName=getTraderLegalName;
this.businessName=businessName;
this.status=status;
}
@Override
public int compareTo(GetTraders1 that) {
return this.getTraderLegalName.compareTo(that.getTraderLegalName);
}
@Override
public String toString() {
return "GetTraders [getTraderLegalName=" + getTraderLegalName + ", businessName=" + businessName + ", status=" + status + "]";
}
public static void main(String[] args) {
GetTraders1 getTraders1 = new GetTraders1("1", "bn", "status");
GetTraders1 getTraders2 = new GetTraders1("2", "bn", "status");
GetTraders1 getTraders3 = new GetTraders1("3", "bn", "status");
List<GetTraders1> list = new ArrayList<>();
list.add(getTraders3);
list.add(getTraders2);
list.add(getTraders1);
System.out.println(list);
Collections.sort(list);
System.out.println(list);
}
}
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2)基于比较器的解决方案
import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;
public class GetTraders2 {
private String getTraderLegalName;
private String businessName;
private Object status;
public GetTraders2(String getTraderLegalName, String businessName, String status) {
this.getTraderLegalName=getTraderLegalName;
this.businessName=businessName;
this.status=status;
}
@Override
public String toString() {
return "GetTraders [getTraderLegalName=" + getTraderLegalName + ", businessName=" + businessName + ", status=" + status + "]";
}
public static void main(String[] args) {
GetTraders2 getTraders1 = new GetTraders2("1", "bn", "status");
GetTraders2 getTraders2 = new GetTraders2("2", "bn", "status");
GetTraders2 getTraders3 = new GetTraders2("3", "bn", "status");
List<GetTraders2> list = new ArrayList<>();
list.add(getTraders3);
list.add(getTraders2);
list.add(getTraders1);
System.out.println(list);
Collections.sort(list, new Comparator<GetTraders2>() {
@Override
public int compare(GetTraders2 o1, GetTraders2 o2) {
return o1.getTraderLegalName.compareTo(o2.getTraderLegalName);
}
});
System.out.println(list);
}
}
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