Z0q*_*Z0q 5 php mysql testing localhost live
我不知道到底发生了什么,但是当我上传我的网站时,我的所有列都只返回了第一个字符.它在本地机器上运行得非常好.
我在这里找到了类似的问题,但我找不到答案:https:
//stackoverflow.com/questions/10507848/mysql-query-returns-only-the-first-letter-of-strings-only-当页面-是-看通
// Log Table Query
unset($stmt);
$stmt = $db->stmt_init();
$stmt = $db->prepare( "SELECT * FROM logs ORDER BY `id` DESC" );
$stmt->store_result();
$stmt->bind_result($r_id, $r_time, $r_logger, $r_message, $r_category);
$stmt->execute();
while( $stmt->fetch() )
{
var_dump($r_message);
var_dump($r_category);
}
$stmt->close();
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这在localhost上输出,例如:
string(5)"Hello"String(3)"Cow"
但在实时服务器上:
string(1)"H"String(1)"C"
有任何想法吗?
编辑
我认为这仅适用于字符串类型.整数类型返回例如:
INT(2893)
我假设您的数据库或表配置与您的localhost类似(最好仔细检查您的表).我注意到一个错误:
1.你打电话store_result()之前打过电话execute().根据http://php.net/manual/en/mysqli-stmt.store-result.php execute()应首先调用.
看到我的代码,这可能会解决您的问题:
/* unsetting doesn't matter you're
going to overwrite it anyway */
unset($stmt);
/* you dont need to initialize $stmt with $db->stmt_init(),
$db->prepare() method will create it for you */
$stmt = $db->stmt_init();
$stmt = $db->prepare("SELECT * FROM logs ORDER BY `id` DESC");
/* execute the query first before storing
the result and binding it your variables */
if (!$stmt->execute()) {
echo "query execution error";
exit();
}
/* store the result */
$stmt->store_result();
/* then bind your variables */
$stmt->bind_result($r_id, $r_time, $r_logger, $r_message, $r_category);
/* fetch data and display */
while($stmt->fetch()) {
var_dump($r_message);
var_dump($r_category);
}
$stmt->close();
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如果这解决了您的问题,请告诉我.
或者,您可以直接使用,因为您没有提供任何类似于WHERE first_name LIKE <input here>您的查询的输入参数:
$result = $db->query("SELECT * FROM logs ORDER BY `id` DESC");
if ($result === false) {
echo "query execution error";
exit();
}
/* You can use either MYSQLI_NUM or MYSQLI_ASSOC os MYSQLI_BOTH
see php.net for more info */
echo "<pre>";
while($line = $result->fetch_array(MYSQLI_NUM)) {
print_r($line);
echo "\n";
}
echo "</pre>";
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