通过 ActivityViewController iOS swift 共享应用程序链接?

Avi*_*are 5 ios uiactivityviewcontroller swift

我的应用程序还没有上线。我从App Store Connect. 我想在社交媒体应用上分享应用链接。我使用了UIActivityViewController

let string1 = "itms-apps://itunes.apple.com/app/idXXXXXXX"
let url = NSURL(string: string1)

let shareItems = [UIApplication.sharedApplication().openURL(url!)]
    
let activityViewController = UIActivityViewController(activityItems: shareItems, applicationActivities: nil)
self.presentViewController(activityViewController, animated: true, completion: nil)
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问题:它没有显示一些社交媒体应用程序,如 WhatsApp。

在此处输入图片说明

Joc*_*zer 15

Swift 4 或更高版本的解决方案:

此解决方案也适用于 iPad(上述解决方案在 iPad 上崩溃):

if let urlStr = NSURL(string: "https://itunes.apple.com/us/app/myapp/idxxxxxxxx?ls=1&mt=8") {
    let objectsToShare = [urlStr]
    let activityVC = UIActivityViewController(activityItems: objectsToShare, applicationActivities: nil)

    if UIDevice.current.userInterfaceIdiom == .pad {
        if let popup = activityVC.popoverPresentationController {
            popup.sourceView = self.view
            popup.sourceRect = CGRect(x: self.view.frame.size.width / 2, y: self.view.frame.size.height / 4, width: 0, height: 0)
        }
    }

    self.present(activityVC, animated: true, completion: nil)
}
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Anb*_*hik 12

这用于打开网站,而不是共享应用程序:

[UIApplication.sharedApplication().openURL(url!)]
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改为这样做:

if let name = URL(string: "https://itunes.apple.com/us/app/myapp/idxxxxxxxx?ls=1&mt=8"), !name.absoluteString.isEmpty {
  let objectsToShare = [name]
  let activityVC = UIActivityViewController(activityItems: objectsToShare, applicationActivities: nil)
  self.present(activityVC, animated: true, completion: nil)
} else {
  // show alert for not available
}
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样品见这个


Leo*_*eon 8

这里的解决方案都很好,但值得考虑实施UIActivityItemSource协议和LinkPresentation框架。

我的解决方案实现了以下目标:

  • 应用程序图标和标题显示在顶部UIActivityViewController
  • 直接链接到 App Store 进行 AirDropActivityType
  • 消息和电子邮件的自定义文本,包括根据需要添加指向 Google Play 上应用程序的链接的机会
  • 电子邮件主题
  • 不使用提取请求(如WWDC 2019 262LPMetaDataProvider视频中所述),因此加载速度更快

0. 初始化UIActivityViewController

将项目设置为self

let activityVC = UIActivityViewController(activityItems: [self], applicationActivities: nil)
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排除某些ActivityType不适用的:

activityVC.excludedActivityTypes = [.addToReadingList, .assignToContact, .markupAsPDF, .openInIBooks, .saveToCameraRoll]
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对于 iPad,设置popoverPresentationController.sourceView.barButtonItem(这在 iPhone 上被忽略):

activityVC.popoverPresentationController?.sourceView = myButton
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呈现它:

present(activityVC, animated: true, completion: nil)
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1. 实现所需的UIActivityItemSource方法

https://developer.apple.com/documentation/uikit/uiactivityitemsource

您必须实现占位符方法,根据文档:

占位符对象不必包含任何实际数据,但应尽可能接近您要提供的实际数据对象进行配置。

func activityViewControllerPlaceholderItem(_ activityViewController: UIActivityViewController) -> Any {
    return ""
}
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以及实际数据,返回 AirDrop 应用程序的链接和其他所有内容的文本:

func activityViewController(_ activityViewController: UIActivityViewController, itemForActivityType activityType: UIActivity.ActivityType?) -> Any? {
    
    if activityType == .airDrop {
        return URL(string: "APP_STORE_URL")!
    }
    
    return "Check out the APP_NAME on the App Store: APP_STORE_URL or on the Google Play Store: PLAY_STORE_URL"
}
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2. 实现主题方法

来自文档:

对于支持主题字段的活动,返回项目的主题。

func activityViewController(_ activityViewController: UIActivityViewController, subjectForActivityType activityType: UIActivity.ActivityType?) -> String {
    return "EMAIL_SUBJECT" // e.g. App name
}
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3. 实现LPLinkMetaData方法

来自文档:

返回要在共享表的预览标题中显示的元数据。

@available(iOS 13.0, *)
func activityViewControllerLinkMetadata(_ activityViewController: UIActivityViewController) -> LPLinkMetadata? {
    let metadata = LPLinkMetadata()
    metadata.title = "APP_NAME"
    return metadata
}
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