如何从无序的Immutable.List()中删除重复项？

Question

如何从无序的Immutable.List()中删除重复项？(不使用toJS()或toArray())

例如

Immutable.List.of("green", "blue","green","black", "blue")

Answer 1

您可以将其转换为Set.集合是具有唯一值的列表.

Immutable.List.of("green", "blue","green","black", "blue").toSet()

如果您再次需要它作为列表,只需将其转换回:

Immutable.List.of("green", "blue","green","black", "blue").toSet().toList()

更新:

获得唯一值的可能性较小:

Immutable.List.of("green", "blue","green","black", "blue").distinct

Answer 2

如果你有一个更复杂的类型,你也可以使用groupBy提供自己的选择器进行比较.以下内容将删除该属性上的重复项.name:

var distinctColors = duplicateColors.groupBy(x => x.name).map(x => x.first()).toList();