如何在OkHttp响应中更改正文？

Question

我正在使用改造.要捕获响应,我正在使用Interceptor:

OkHttpClient okHttpClient = new OkHttpClient();
okHttpClient.interceptors().add(myinterceptor);

这是拦截器的代码:

new Interceptor() {
    @Override
    public Response intercept(Chain chain) throws IOException {
        Request request = chain.request();
        Response response = chain.proceed(request);
        if (path.equals("/user")){
            String stringJson = response.body().string();
            JSONObject jsonObject = new JSONObject(stringJson);
            jsonObject.put("key",1);
            //here I need to set this new json to response and then return this response

如何在OkHttp响应中更改正文？

Answer 1

加上这个

MediaType contentType = response.body().contentType();
ResponseBody body = ResponseBody.create(contentType, jsonObject);
return response.newBuilder().body(body).build();

在您的回复修改后.jsonObject是您要返回的已修改JSON.

Answer 2

下面是Response Intercepter类,您可以在其中拦截okkhttp响应并添加您自己的响应.并将其发送给改造.

import org.json.JSONException;
import org.json.JSONObject;

import java.io.IOException;

import okhttp3.Interceptor;
import okhttp3.MediaType;
import okhttp3.Request;
import okhttp3.ResponseBody;
import retrofit2.Response;

public class ApiResponseInterceptor implements Interceptor {

    @Override
    public okhttp3.Response intercept(Chain chain) throws IOException {
        Request request = chain.request();
        okhttp3.Response response = chain.proceed(request);
        if(response.code() == 200) {
            JSONObject jsonObject = new JSONObject();
            try {
                jsonObject.put("code",200);
                jsonObject.put("status","OK");
                jsonObject.put("message","Successful");

                MediaType contentType = response.body().contentType();
                ResponseBody body = ResponseBody.create(contentType, jsonObject.toString());
                return response.newBuilder().body(body).build();
            } catch (JSONException e) {
                e.printStackTrace();
            }
        } else if(response.code() == 403) {

        }
        return response;
    }
}

您将在改装回调中获得修改后的响应

call.enqueue(new Callback<EventResponce>() {
            @Override
            public void onResponse(Call<EventResponce> call, Response<EventResponce> response) {
                // you will get your own modified responce here
            }

            @Override
            public void onFailure(Call<EventResponce> call, Throwable t) {

            }
        });

Answer 3

作为一个较小的更改，我不会使用该string()方法，因为在此请求上只能调用一次。您确实使用了response.newBuilder()其他拦截器，因此可以调用string()您的新拦截器，但是我发现自己浪费了几个小时，因为我实际上两次调用了：P。

所以我建议如下

BufferedSource source = response.body().source();
source.request(Long.MAX_VALUE); // Buffer the entire body.
Buffer buffer = source.buffer();
String responseBodyString = buffer.clone().readString(Charset.forName("UTF-8"));