mac*_*kee 0 javascript php jquery
继承了我的问题,当我试图将我的数据发送到PHP时,它只发送<button>或的值<input type="button">.
如果我删除了变量的定义,它只会将数据作为字符串发送,如果我有这样的话
newusername: "newusername",
newpassword: "newpassword",
newclub: "newclub"
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如果我删除了""我将在jquery.mini.js中得到一个错误
HTML:
<form method="post">
<div class="form-group">
<label> Username </label>
<input type="text" class="form-control" id="newusername">
</div>
<div class="form-group">
<label> Password </label>
<input type="password" class="form-control" id="newpassword">
</div>
<div class="form-group">
<label> Your club </label>
<input type="text" class="form-control" id="newclub">
</div>
<input type="button" id="btn-reg">
</form>
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使用Javascript:
console.log('Script loaded...');
$("#btn-reg").on("click", reg);
function reg(newusername, newpassword, newclub) {
console.log('Klick, klick...');
var newusername = $(this).val();
var newpassword = $(this).val();
var newclub = $(this).val();
$.post('classCalling.php', {
newusername: "newusername",
newpassword: "newpassword",
newclub: "newclub"
},
function(data){
console.log(data);
});
}
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小智 5
我看到两件事:
发送的对象的定义很糟糕.该对象由键值对组成,您将其设置为硬编码的字符串值.
开头的变量捕获$(this).val()都是一样的.您没有将其作为DOM对象获取.您应该在括号中进行CSS查询(即$("---this--")).
function reg(newusername, newpassword, newclub) {
console.log('Klick, klick...');
// if there is a input with class newusernameand only one
var newusername = $('input.newusername').val();
//if there is a input with class newpassword and only one
var newpassword = $('input.newpassword').val();
//if there is a input with class newclub and only one
var newclub = $('input.newclub').val();
$.post('classCalling.php',
{
newusername: newusername,
newpassword: newpassword,
newclub: newclub
},
function(data) {
console.log(data);
});
}
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