我是 python 和编程新手,通常我的文件夹中有 1200 个文本文件,格式如下:
James - 1 - How to... .txt
Sarah - 2 - How to... .txt
Steph - 3 - How to ... .txt
...
玛丽亚 - 200 - 如何... .txt
...
拉什福德 - 1200 - 如何... .txt
我想重命名 1000 以下的文件以添加前导 0,以便它们都具有相同的位数,例如 0001、0050、0300
到目前为止,这是我的代码,但我卡住了:
#!python3
import os
from tkinter import filedialog
cleaned_files = []
root_folder = filedialog.askdirectory()
os.chdir(root_folder)
folder_files = os.listdir(root_folder)
# Filter out files starting with '.' and '_'
cleaned_files = []
for item in folder_files:
if item[0] == '.' or item[0] == '_':
pass
else:
cleaned_files.append(item)
# Find file names of the root folder and save them
def getFiles(files):
for file in files:
file_start, file_number, file_end = file.split('-')
file_number.strip()
# Was trying to append just one 0 to numbers <10
if int(file_number) < 10:
print(file_number)
else:
pass
getFiles(cleaned_files)
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正如您在评论中所说,str.zfill这是一种可能且简单的解决方案。
你只需要改变你的getfiles功能:
def getFiles(files):
for file in files:
file_start, file_number, file_end = file.split('-')
num = file_number.split().zfill(4) # num is 4 characters long with leading 0
new_file = "{}- {} -{}".format(file_start, num, file_end)
# rename or store the new file name for later rename
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