如何使用 Sequelize 通过原始查询获取最后插入的 ID?

Bra*_*ton 5 javascript mysql node.js sequelize.js

在 sequelize.js 中尝试以下原始 MySQL 插入时:

mysql_sequelize.query( 'INSERT IGNORE INTO steamer(steamer_id, prov_id, name, avatar) VALUES(UNHEX(REPLACE(UUID(),\'-\',\'\')), \'' + prov_id + '\', \'' + steamer_name + '\', \'' + steamer_avatar + '\')')
  .then(function (data) {
       console.log('inserted STEAMER data---> ',data);  // no useful info
  });
);
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生成的控制台日志如下所示:

inserted STEAMER data--->  [ OkPacket {
    fieldCount: 0,
    affectedRows: 1,
    insertId: 0,
    serverStatus: 2,
    warningCount: 1,
    message: '',
    protocol41: true,
    changedRows: 0 },
  OkPacket {
    fieldCount: 0,
    affectedRows: 1,
    insertId: 0,
    serverStatus: 2,
    warningCount: 1,
    message: '',
    protocol41: true,
    changedRows: 0 } ]
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我该怎么做才能获得以下数据的 ID?甚至最后插入的ID?

lin*_*lin 6

您可以通过{ type: sequelize.QueryTypes.INSERT }作为选项参数传递来实现此目的。这将使sequelize返回插入它。

简单查询示例:

sequelize.query(
    "INSERT INTO clients (name) values ('myClient')",
    { type: sequelize.QueryTypes.INSERT }
).then(function (clientInsertId) {
    console.log(clientInsertId);
});
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  • 对于 postgresql,您需要包含“RETURNING id” (4认同)