Wob*_*bly 4 c++ gcc operator-precedence
std::cout << (abs(b - c) < a) && a < b + c ? 1 : 0;
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我想检查给定的值是否可以创建三角形.我收到了警告:
second operand of conditional expression has no effect [-Wunused-value]
third operand of conditional expression has no effect [-Wunused-value]
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怎么了?
Log*_*uff 10
您的代码转换为:
((std::cout << (abs(b - c) < a)) && a < b + c) ? 1 : 0;
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首先,operator<<具有更高的运算符优先级比operator&&.
仅abs(b - c) < a打印值,(a < b + c ? 1 : 0)零件将与返回值一起进行AND运算std::ostream::operator bool.
但警告是关于1并且0没有分配给任何东西也没有任何副作用,因为&&在三元条件(?:)之前.
正确的代码是:
std::cout << (abs(b - c) < a && a < b + c ? 1 : 0);
// same as std::cout << ((abs(b - c) < a && a < b + c) ? 1 : 0);
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要么
std::cout << (abs(b - c) < a && (a < b + c ? 1 : 0));
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事实上,他们是相当的(除了一个电话operator<<与bool和其他与int),没有三元操作需要:
std::cout << (abs(b - c) < a && a < b + c);
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