使用存储过程将文件插入到SQL Server而不使用前端

Question

我试图通过SQL插入文件.我使用以下查询.

INSERT INTO [dbo].[Attachments] (FileName, FileBinary)
    SELECT 
        'non-date-in-sql-server-column', 
        BulkColumn 
    FROM 
        OPENROWSET(Bulk 'C:\Users\Pictures\Picture.JPG', SINGLE_BLOB) AS BLOB

它工作正常.

我想编写采用动态路径的过程.它给了我错误,我不能把文件箱加入.哪个是数据类型varbinary.什么是最好的方法？

我已经完成了以下但是没有采用正确的二进制值.

DECLARE @SQLString NVARCHAR(MAX)

SET @SQLString = 'SELECT ' + '''' +@Filename +'''' + ' AS Name,' +  'FileBinary

FROM OPENROWSET(BULK N''' + @ImagePath + ''',SINGLE_BLOB) AS FileBinary(FileBinary);'

Insert Into Attachments (ApplicantID, FileName, FileBinary)
Values (@ApplicantID, @FileName, Convert(varbinary(max), @SQLString))

Answer 1

将 Insert 语句放入动态查询中并执行它。

现在您@SQLString将没有该FileBinary值，它将具有动态框架字符串。您需要执行它才能获取值

DECLARE @SQLString   NVARCHAR(MAX),
        @Filename    VARCHAR(500), -- Pass file name here
        @ApplicantID VARCHAR(500) --Pass Application ID here

SET @SQLString = '
    Insert Into Attachments
    (
            ApplicantID,
            FileName,
            FileBinary
    )
    SELECT @ApplicantID,@Filename,FileBinary
    FROM OPENROWSET(BULK N''' + @ImagePath
                 + ''',SINGLE_BLOB) AS FileBinary(FileBinary);'

EXEC Sp_executesql
  @SQLString,
  N'@Filename varchar(500),@ApplicantID varchar(500)',
  @Filename =@Filename,
  @ApplicantID=@ApplicantID