如何在mysqli中运行选择查询

Question

我需要显示特定记录，记录存在于 db 中，但它什么也没显示。这是我的代码。

 $con=mysqli_connect("localhost","root","","test") or die("Connecting to MySQL failed"); 


$name=$_POST['uname'];

$query = "SELECT * FROM officedb WHERE name='.$name.'";
$data=mysqli_query($con,$query);   

while($row=mysqli_fetch_array($data)){
    echo $row['name'];
    echo $row['lname'];
    echo $row['department'];
}

Answer 1

您连接$name变量错误，只需更改：

$query = "SELECT * FROM officedb WHERE name='.$name.'";

有了这个：

$query = "SELECT * FROM officedb WHERE name = '$name'";

您的查询如下所示：

SELECT * FROM officedb WHERE name = '.test.'

按照我的建议进行更改后，查询应该是：

SELECT * FROM officedb WHERE name = 'test'