需要帮助使用PHP在mysql数据库中插入逗号分隔数据

Question

数据库表中已有的演示数据:

INSERT INTO `csvtbl` (`ID`, `SKU`, `Product_Name`, `Model`, `Make`, `Year_From`, `Year_To`) VALUES
(1, 'C2AZ-3B584-AR', 'Power Steering Pump Seal Kit (Eaton Pump)', 'Galaxie', 'Ford', '1960', '1965'),
(2, 'C2AZ-3B584-AR', 'Power Steering Pump Seal Kit (Eaton Pump)', 'Thunderbird ', 'Fordtrest', '1960', '1965');

我使用下面的代码并插入年份,并在表格中分隔逗号(,):

INSERT INTO `diff_yearstbl` (`ID`, `SKU`, `Product_Name`, `Model`, `Make`, `Year`) VALUES
(1, 'C2AZ-3B584-AR', 'Power Steering Pump Seal Kit (Eaton Pump)', 'Galaxie', 'Ford', '1960,1961,1962,1963,1964,1965'),
(2, 'C2AZ-3B584-AR', 'Power Steering Pump Seal Kit (Eaton Pump)', 'Thunderbird ', 'Fordtrest', '1960,1961,1962,1963,1964,1965');

年份数据运行良好,但我想插入数据Make和Model与Year相同,但这次只是使用逗号(,)将数据插入一行,如下例所示,使用SKU字段.因此需要将上述两条记录合并为一行,如下面的记录.

INSERT INTO `diff_yearstbl` (`ID`, `SKU`, `Product_Name`, `Model`, `Make`, `Year`) VALUES
(1, 'C2AZ-3B584-AR', 'Power Steering Pump Seal Kit (Eaton Pump)', 'Galaxie, Thunderbird', 'Ford, Fordtrest' '1960,1961,1962,1963,1964,1965');

以下是我所做的代码:

    $query = "select Year_TO - Year_From as diff_years, ID, SKU,Product_Name,Model,Make,Year_From,Year_To from csvtbl";
$result = mysql_query($query, $connect );

//$result = $db->query($select_test)->fetchAll();

if (count($result) > 0) 
{

    while($QryRow = mysql_fetch_assoc($result)) 
    {
        $diff_years = $QryRow['diff_years'];
        $Year_From = $QryRow['Year_From'];
        $SKU = $QryRow['SKU'];
        $Product_Name = $QryRow['Product_Name'];
        $Model = $QryRow['Model'];
        $Make = $QryRow['Make'];

        $years= array();
        for ($x = $QryRow['Year_From']; $x <= $QryRow['Year_To']; $x++) 
        {           
            $years[] = $x;    
        }

        $query_insert = "INSERT INTO diff_yearstbl(SKU,Product_Name,Model,Make,Year) VALUES('".$SKU."','".$Product_Name."','".$Model."','".$Make."','".implode('|',$years)."')";
        $s_insert = mysql_query($query_insert, $connect ); 
    }
} 
else 
{
    echo "<p>Nothing matched your query.</p>";
}

    ?>

请帮忙一下.

Answer 1

您应该从 循环$QryRow['Year_From']到$QryRow['Year_To']并将它们全部收集起来，然后再插入它们。

$years= array();
for ($x = $QryRow['Year_From']; $x <= $QryRow['Year_To']; $x++) 
{           
    $years[] = $x;    
}

$query_insert = "INSERT INTO diff_yearstbl(SKU,Product_Name,Model,Make,Year) VALUES('".$SKU."','".$Product_Name."','".$Model."','".$Make."','".implode(',',$years)."')";
$s_insert = mysql_query($query_insert, $connect ); 

mysql_* 已弃用， 请使用mysqli_* 或 PDO