hea*_*l91 2 laravel laravel-5 laravel-5.1
输入返回问题。提交表单后,如果验证程序失败,则不返回“旧”输入。这是我的控制器
$validator = Validator::make($request->all(), [
'user_rate' => 'required|integer|between:1,5',
'user_comment' => 'required',
], [
"user_rate.integer" => trans('errors.rate-required'),
"user_rate.between" => trans('errors.rate-required'),
"user_rate.required" => trans('errors.rate-required'),
"user_comment.required" => trans('errors.com-required'),
]);
if ($validator->fails()) {
return redirect()->back()->withErrors($validator)->withInput($request->input());
//return redirect()->back()->with(Input::all());
}
Run Code Online (Sandbox Code Playgroud)
我尝试了几种方法(也$ request-> flash(),但它不返回“旧”输入
在您的控制器中
public function someFunction(Request $request)
{
//Validation Logic
if($v->fails())
{
return redirect()->back()->withInput();
}
}
Run Code Online (Sandbox Code Playgroud)
在您看来
<input type="text" name="some_name" value="{{old('some_name')}}">
Run Code Online (Sandbox Code Playgroud)
希望这可以帮助。
归档时间: |
|
查看次数: |
1737 次 |
最近记录: |