ls()有一个pattern参数 - 见?ls.要在任何地方搜索"a":
> ls(pattern='a')
[1] "a" "clean" "extractRawText" "extractRSS" "extractText" "parts" "raw.data"
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或者使用正则表达式来获取以"A"开头的内容:
> ls(pattern='^A')
[1] "A" "Act"
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如果你不了解正则表达式,但知道像'*'这样的通配符,你可以使用glob2rx():
> ls(pattern=glob2rx("A*"))
[1] "A" "Act"
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