我有一个简单的Sum扩展:
public static int? SumOrNull<TSource>(this IEnumerable<TSource> source, Func<TSource, int> projection)
{
return source.Any()
? source.Sum(projection)
: (int?)null;
}
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但它会导致 System.OverflowException: Arithmetic operation resulted in an overflow.
我想要做的是这样的事情:
public static ulong? SumOrNull<TSource>(this IEnumerable<TSource> source, Func<TSource, int> projection)
{
return source.Any()
? source.Sum(projection)
: (ulong?)null;
}
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但Linq Sum没有超载,因此返回ulong和编译错误.任何方式使这项工作?
您可以手动实现它.这是一个例子:
public static ulong? SumOrNull<TSource>(
this IEnumerable<TSource> source,
Func<TSource, int> projection)
{
bool any = false;
ulong sum = 0;
foreach (var item in source)
{
any = true;
//As commented by CodesInChaos,
//we use the checked keyword to make sure that
//we throw an exception if there are any negative numbers
sum = sum + (ulong)checked((uint)projection(item));
}
if (!any)
return null;
return sum;
}
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