SQL高分

Question

好的,我有两个MYSQL表:

CREATE TABLE `sessions` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `userID` int(11) NOT NULL,
  `runTime` int(11) NOT NULL,
  `monstersKilled` int(11) NOT NULL,
  `profit` int(11) NOT NULL,
  `tasks` int(11) NOT NULL,
  `xpGain` int(11) NOT NULL,
  `lastupdate` int(11) NOT NULL,
  PRIMARY KEY (`id`)
);

和,

CREATE TABLE  `users` (
  `userid` int(11) NOT NULL AUTO_INCREMENT,
  `user` text NOT NULL,
  `pass` text NOT NULL,
  `paypal` text NOT NULL,
  `active` tinyint(1) NOT NULL DEFAULT '0',
  `strikes` int(11) NOT NULL DEFAULT '0',
  `session` text NOT NULL,
  `brand` text NOT NULL,
  `identifier` text NOT NULL,
  PRIMARY KEY (`userid`)
) ENGINE=MyISAM AUTO_INCREMENT=651 DEFAULT CHARSET=latin1;

如您所见,会话具有指向用户ID的链接.现在我想制作一个总分高的PHP文件,但凭借我对PHP的一点知识和对MYSQL的了解不多,我不知道如何开始.总得分将按总运行时间排序.

示例:在用户中,我有用户#1(cody)和用户#2(Joe).现在,在会议中我有3个会话:

id, userID, runTime, monstersKilled, profit, tasks, xpGain, lastupdate
12, 1, 27, 14, 6200, 0, 5050, 1282325410
19, 1, 18, 1, 277, 1, 168, 1278897756
1968, 2, 195, 433, 111345, 4, 73606, 1280993244

打印出来应该是:

Place, username, Total Run Time, Total Monsters Killed, Total profit, Total tasks, Total Exp Gain
1. Joe, 195, 433,11345,4,73606
2. Cody, 55, 15, 1, 5218

Answer 1

使用:

  SELECT u.user,
         SUM(s.runtime) AS total_run_time,
         SUM(s.monsterskilled) AS total_monsters_killed,
         SUM(s.profit) AS total_profit,
         SUM(s.tasks) AS total_tasks, 
         SUM(s.xpgain) AS total_xp_gained
    FROM USERS u
    JOIN SESSION s ON s.userid = u.userid
GROUP BY u.user
ORDER BY total_run_time DESC