qua*_*ela 1 java json jackson guava jackson-modules
我有两个Map对象,将它们合并到Guava的Multimap中。合并后,我试图通过杰克逊序列化映射最终ObjectMapper用GuavaModule(否则它不序列正确)。但是,问题是,即使只有一个值,键的每个值也会作为列表的元素打印出来(objectmapper用方括号将每个值包装起来)。我得到的基本输出如下
{
"address": {
"city": ["san francisco"]
},
"company": {
"employees": [
[{
"name": "David",
"lastname": "Foobar",
"age": 22
}, {
"name": "Michael",
"lastname": "FizBuzz",
"age": 35
}]
]
},
"config": {
"key1": ["value1", "value3"],
"key2": ["value2"],
"key4": ["value4"]
}
}
Run Code Online (Sandbox Code Playgroud)
如您所见,“地址”->“城市”->“旧金山”用方括号company -> employees包裹,也用两次包裹。此外,我已经尝试过SerializationFeature.WRITE_SINGLE_ELEM_ARRAYS_UNWRAPPED, trueFuture,但没有任何改变。
Person person = new Person();
person.setName("David");
person.setLastname("Foobar");
person.setAge(22);
Person person2 = new Person();
person2.setName("Michael");
person2.setLastname("FizBuzz");
person2.setAge(35);
Map<String, Map<String, Object>> map1 = new ImmutableMap.Builder<String, Map<String, Object>>()
.put("config", ImmutableMap.of(
"key1", "value1",
"key2", "value2"))
.put("address", ImmutableMap.of("city", "san francisco"))
.put("company", ImmutableMap.of("employees", Arrays.asList(person, person2)))
.build();
Map<String, Map<String, Object>> map2 = new ImmutableMap.Builder<String, Map<String, Object>>()
.put("config", ImmutableMap.of(
"key1", "value3",
"key4", "value4"))
.build();
Map<String, Multimap<String, Object>> merged = new HashMap<>();
BiFunction<Multimap<String, Object>,
Multimap<String, Object>,
Multimap<String, Object>> remappingFunction = (value1, value2) -> {
Multimap<String, Object> multimap = HashMultimap.<String, Object>create();
multimap.putAll(value1);
multimap.putAll(value2);
return multimap;
};
map1.forEach((key, value) -> merged.merge(key, Multimaps.forMap(value), remappingFunction));
map2.forEach((key, value) -> merged.merge(key, Multimaps.forMap(value), remappingFunction));
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.registerModule(new GuavaModule());
objectMapper.configure(SerializationFeature.WRITE_SINGLE_ELEM_ARRAYS_UNWRAPPED, true);
String str = objectMapper.writeValueAsString(merged);
System.out.print(str);
}
Run Code Online (Sandbox Code Playgroud)
感谢您的帮助。谢谢
根据Jackson的文档,MultimapSerializer“将所有值集都封装在JSON数组中,而与值的数量无关”。我相信这意味着它实际上是在忽略该WRITE_SINGLE_ELEM_ARRAYS_UNWRAPPED功能。
您可以通过在序列化之前将所有内部Multimap<String, Object>实例转换为标准Map<String, Collection<Object>>实例来避免此问题。您可以使用Multimap.asMap()以下方法执行此操作:
Map<String, Map<String, Collection<Object>>> newMerged = new HashMap<>();
merged.forEach((key, value) -> newMerged.put(key, value.asMap()));
String newStr = objectMapper.writeValueAsString(newMerged);
System.out.println(newStr);
Run Code Online (Sandbox Code Playgroud)
这将输出您期望的输出:
{"address":{"city":"san francisco"},"company":{"employees":[{"name":"David","lastname":"Foobar","age":22},{"name":"Michael","lastname":"FizBuzz","age":35}]},"config":{"key1":["value1","value3"],"key2":"value2","key4":"value4"}}
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
1970 次 |
| 最近记录: |