新的快速.不确定为什么编译器会给出以下代码的错误:
func addNumbers(numbers: Int ...) -> Int {
var total : Int = 0
for number in numbers {
total += number
}
return total
}
func multiplyNumbers(numbers: Int ...) -> Int {
var total : Int = numbers [0]
for (index,number) in numbers.enumerate() {
if index == 0 {
continue
}
total *= number
}
return total
}
func mathOperation(mathFunction: (Int ...) -> Int, numbers: Int ...) -> Int {
return mathFunction(numbers)
}
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错误:
错误:无法将类型'[Int]'的值转换为预期的参数类型'Int'返回mathFunction(数字)
Swift varargs不太容易使用.我会将参数类型更改为Arrays.这是一个有效的解决方案:
func addNumbers(numbers: [Int]) -> Int {
var total : Int = 0
for number in numbers {
total += number
}
return total
}
func multiplyNumbers(numbers: [Int]) -> Int {
var total : Int = numbers [0]
for (index,number) in numbers.enumerate() {
if index == 0 {
continue
}
total *= number
}
return total
}
func mathOperation(mathFunction: [Int] -> Int, numbers: Int ...) -> Int {
return mathFunction(numbers)
}
print(mathOperation(multiplyNumbers,numbers: 3,24))
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这将打印出来 72
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