谁可以给我这个程序的干输出?

shu*_*aat 1 c

谁可以给我这个程序的干输出?

#include <stdio.h>
main()
{
int a,b,c,d,e;
printf("Enter the Number to Find it's Reverse\n");
scanf("%d",&a);
while(a!=0)
{
b=a%10;
c=a/10;
printf("%d",b);
a=c;
}
getchar();
}
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And*_*sne 5

假设从干输出你的意思是代码的解释,这是我的尝试.

假设用户输入143.所以现在a = 143.

while( a != 0 )  // a = 143 therefor condition is true and the block of
                 // code inside the loop is executed.
b =  a % 10 ;  // 143 % 10  ( The remainder is 3 )
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所以价值b印在屏幕上

3

现在

c = a / 10 ;  // 143 / 10 =  14  
a = c ;       // so now a = 14
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再一次,我们回到了 while()

while( a != 0 )  // a = 14 therefor condition is true and the block of
                 // code inside the loop is executed.
b =  a % 10 ;  // 14 % 10  ( The remainder is 4 )
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因此,价值b已印在屏幕上,已有3

34

现在

c = a / 10 ;  // 14 / 10 =  1
a = c ;       // so now a = 1
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再次,我们回到了 while()

while( a != 0 )  // a = 1 therefor condition is true and the block of
                 // code inside the loop is executed.
b =  a % 10 ;  // 1 % 10  ( its output will be 1 )
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所以b在已有的屏幕上打印的价值34

341

现在

c = a / 10 ;  // 1 / 10 =  0
a = c ;       // so now a = 0
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我们回到了 while()

while( a != 0 )  // a = 0 therefor condition is FALSE and the block of
                 // code inside the loop is NOT executed.
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希望它有所帮助.
注意
而不是

c=a/10;
a=c;
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你可以简单地写

a /= 10
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其次,

int a,b,c,d,e;
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目的是e什么?