计算每个字母在文本样本中出现的次数

Question

我需要一个函数来计算每个字母出现在字符串中的次数.它必须将大写字母和小写字母统计为相同的字母.我有点做了,但它并不完美.

def lmao(x):

    aye=x.count("a")
    Aye=x.count("A")
    bye=x.count("b")
    Bye=x.count("B")
    cye=x.count("c")
    Cye=x.count("C")
    dye=x.count("d")
    Dye=x.count("D")
    Eye=x.count("E")
    eye=x.count("e")
    Fye=x.count("F")
    fye=x.count("f")
    Gye=x.count("G")
    gye=x.count("g")
    Hye=x.count("H")
    hye=x.count("h")
    Iye=x.count("I")
    iye=x.count("i")
    Jye=x.count("J")
    jye=x.count("j")
    Kye=x.count("K")
    kye=x.count("k")
    Lye=x.count("L")
    lye=x.count("l")
    Mye=x.count("M")
    mye=x.count("m")
    Nye=x.count("N")
    nye=x.count("n")
    Oye=x.count("O")
    oye=x.count("o")
    Pye=x.count("P")
    pye=x.count("P")
    Qye=x.count("Q")
    qye=x.count("q")
    rye=x.count("r")
    Rye=x.count("R")
    sye=x.count("s")
    Sye=x.count("S")
    tye=x.count("t")
    Tye=x.count("T")
    uye=x.count("u")
    Uye=x.count("U")
    Vye=x.count("V")
    vye=x.count("v")
    Wye=x.count("W")
    wye=x.count("w")
    Xye=x.count("X")
    xye=x.count("x")
    Yye=x.count("Y")
    yye=x.count("y")
    Zye=x.count("Z")
    zye=x.count("z")
    killme=(aye+Aye,bye+Bye,cye+Cye,Dye+dye,Eye+eye,Fye+fye,Gye+gye,Hye+hye,Iye+iye,jye+Jye,Kye+kye,Lye+lye,Mye+mye,Nye+nye,Oye+oye,Pye+pye,Qye+qye,rye+Rye,sye+Sye,Tye+tye,uye+Uye,Vye+vye,Wye+wye,xye+Xye,Yye+yye,Zye+zye)
    return killme

所以,是的,那就是我想出的灾难.有没有办法缩短这个过程？

Answer 1

使用collections.Counter https://docs.python.org/2/library/collections.html#counter-objects

from collections import Counter    
counter = Counter(mystr.lower())

会给你所有出现的每个字母,忽略大小写