python datetime以毫秒精度浮动

Question

什么是在python中以毫秒精度在float中存储日期和时间信息的优雅方法？编辑:我正在使用python 2.7

我一起攻击了以下内容:

DT = datetime.datetime(2016,01,30,15,16,19,234000) #trailing zeros are required
DN = (DT - datetime.datetime(2000,1,1)).total_seconds()
print repr(DN)

输出:

507482179.234

然后恢复到日期时间:

DT2 = datetime.datetime(2000,1,1) + datetime.timedelta(0, DN)
print DT2

输出:

2016-01-30 15:16:19.234000

但我真的在寻找一些更优雅,更健壮的东西.

在matlab中我会使用datenum和datetime函数:

DN = datenum(datetime(2016,01,30,15,16,19.234))

并回复:

DT = datetime(DN,'ConvertFrom','datenum')

Answer 1

Python 2:

def datetime_to_float(d):
    epoch = datetime.datetime.utcfromtimestamp(0)
    total_seconds =  (d - epoch).total_seconds()
    # total_seconds will be in decimals (millisecond precision)
    return total_seconds

def float_to_datetime(fl):
    return datetime.datetime.fromtimestamp(fl)

Python 3:

def datetime_to_float(d):
    return d.timestamp()

float_to_datetime 会是一样的.

Answer 2

在Python 3，你可以使用：timestamp（和fromtimestamp为倒数）。

例子：

>>> from datetime import datetime
>>> now = datetime.now()
>>> now.timestamp()
1455188621.063099
>>> ts = now.timestamp()
>>> datetime.fromtimestamp(ts)
datetime.datetime(2016, 2, 11, 11, 3, 41, 63098)