Google Mock:在EXPECT_CALL中设置参数

Pau*_*iss 2 c++ oop unit-testing googletest googlemock

我正在尝试在Google Mock中设置类成员函数参数值,但出现构建错误,而且我根本不了解发生了什么。有人可以解释一下吗?

函数原型为:

virtual int recv( Socket socket
                , char *buffer
                , int bufferLength
                , int flags ) = 0;
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我正在尝试使用以下方法进行测试:

TEST_F( IPV4SocketTests, Read_SockErr_ok )
{
    Mock_SocketAdaptor *adaptor = new Mock_SocketAdaptor;
    char *rcvBuffer = "testingRcvWorks";

    EXPECT_CALL( *adaptor, recv( testing::_, testing::_, testing::_, testing::_ ) )
    .WillRepeatedly( testing::DoAll(
        testing::SetArgPointee<1>( rcvBuffer ),
        testing::Return( strlen( rcvBuffer ) ) ) );
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我收到的错误是关于从std :: get进行的转换。

Mar*_*vic 5

问题是那rcvBuffer是一个指针。这就是为什么在设置指针时必须取消引用它的原因。这是您的EXPECT_CALL外观:

EXPECT_CALL( *adaptor, recv( testing::_, testing::_, testing::_, testing::_ ) )
    .WillRepeatedly( testing::DoAll(
        testing::SetArgPointee<1>( *rcvBuffer ),
        testing::Return( strlen( rcvBuffer ) ) ) );
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编辑:

这是我在项目中用来模拟通过用作参数的指针返回char数组的方法。首先,您需要创建一个自定义操作,该操作将复制缓冲区的内容(SetArrayArgument在这种情况下,您不能使用):

ACTION_TEMPLATE(SetArgNPointeeTo, HAS_1_TEMPLATE_PARAMS(unsigned, uIndex), AND_2_VALUE_PARAMS(pData, uiDataSize))
{
    std::memcpy(std::get<uIndex>(args), pData, uiDataSize);
}
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然后,在测试中像这样使用它:

Mock_SocketAdaptor *adaptor = new Mock_SocketAdaptor;
char rcvBuffer[] = "testingRcvWorks";
size_t bufferSize = sizeof("testingRcvWorks");

EXPECT_CALL( *adaptor, recv( testing::_, testing::_, testing::_, testing::_ ) )
    .WillRepeatedly( testing::DoAll(
        SetArgNPointeeTo<0>(std::begin(rcvBuffer), bufferSize),
        testing::Return( strlen( rcvBuffer ) ) ) );
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