Asterisk ARI 电话会议应用程序：授权/询问密码

Question

我正在使用 C#/.NET库来实现Asterisk RESTful 接口 (ARI)来创建电话会议应用程序。

到目前为止，该应用程序的工作方式如下：

1. 用户拨打该号码
2. 应用答案
3. 应用程序启动语音检测
4. 应用程序询问姓名并录制音频
5. 应用程序将用户添加到会议

要求：

在将用户添加到会议之前，我需要在上述过程中添加某种授权。我需要实现要求输入 PIN 码的功能，创建一个 PIN 码结构，如果来电者输入正确的 PIN 码，则将来电者添加到正确的电话会议中。

编码：

会议：

    public Conference( AriClient c, Guid id, string name)
    {
        _client = c;
        Id = id;
        ConferenceName = name;
        State = ConferenceState.Destroyed;

        c.OnChannelDtmfReceivedEvent += c_OnChannelDtmfReceivedEvent; // ??
        c.OnBridgeCreatedEvent += c_OnBridgeCreatedEvent;
        c.OnChannelEnteredBridgeEvent += c_OnChannelEnteredBridgeEvent;
        c.OnBridgeDestroyedEvent += c_OnBridgeDestroyedEvent;
        c.OnChannelLeftBridgeEvent += c_OnChannelLeftBridgeEvent;
        c.OnRecordingFinishedEvent += c_OnRecordingFinishedEvent;

        // Added support for talk detection
        c.OnChannelTalkingStartedEvent += c_OnChannelTalkingStartedEvent;
        c.OnChannelTalkingFinishedEvent += c_OnChannelTalkingFinishedEvent;

        Debug.Print("Added Conference {0}", ConferenceName);
    }

OnChannelEnteredBridgeEvent:

private void c_OnChannelEnteredBridgeEvent(object sender, ChannelEnteredBridgeEvent e)
{
    ConferenceUser confUser = ConferenceUsers.SingleOrDefault(x => x.Channel.Id == e.Channel.Id);
    if (confUser == null) return;

    confUser.State = ConferenceUserState.InConf;

    if (ConferenceUsers.Count(x => x.State == ConferenceUserState.InConf) > 1) // are we the only ones here
    {
        // stop moh
        _client.Bridges.StopMoh(Confbridge.Id);

        // change state
        State = ConferenceState.Ready;

        // announce new user
        _client.Bridges.Play(Confbridge.Id, "recording:" + confUser.CurrentRecodingId, "en", 0, 0, Guid.NewGuid().ToString());
        _client.Bridges.Play(Confbridge.Id, "sound:conf-hasjoin", "en", 0, 0, Guid.NewGuid().ToString());
    }
    else
    {          
        // only caller in conf
        _client.Channels.Play(e.Channel.Id, "sound:conf-onlyperson", "en", 0, 0, Guid.NewGuid().ToString());
    }
}

开始会议：

    public bool StartConference()
    {

        // Create the conference bridge
        Debug.Print("Requesting new bridge {0} for {1}", Id, ConferenceName);
        Bridge bridge = _client.Bridges.Create("mixing", Id.ToString(), ConferenceName);

        if (bridge == null)
        {
            return false;
        }

        Debug.Print("Subscribing to events on bridge {0} for {1}", Id, ConferenceName);
        _client.Applications.Subscribe(AppConfig.AppName, "bridge:" + bridge.Id);

        // Start MOH on conf bridge
        _client.Bridges.StartMoh(bridge.Id, "default");

        // Default state is ReadyWaiting until MOH is turned off
        State = ConferenceState.ReadyWaiting;
        Confbridge = bridge;

        // Conference ready to accept calls
        State = ConferenceState.Ready;

        return true;
    }

添加用户：

    public bool AddUser(Channel c) //here check for pin and caller id
    {
        if (State == ConferenceState.Destroying)
            return false;
        if (State == ConferenceState.Destroyed)
        {
            // We should initiate a new conference bridge
            if (!StartConference())
                return false;
        }
        if (State < ConferenceState.Ready) return false;

        // Answer channel
        _client.Channels.Answer(c.Id);

        // Turn on talk detection on this channel
        _client.Channels.SetChannelVar(c.Id, "TALK_DETECT(set)", "");

        // Add conference user to collection
        ConferenceUsers.Add(new ConferenceUser(this, c, _client, ConferenceUserType.Normal));

        return true;
    }

题：

如何在应用程序中引发/调用“询问密码”事件/通道并将输入的 DTMF 数字抓取到变量中？

这可以仅在我的 C# ARI 应用程序中完成，还是需要在 Asterisk 服务器上处理 .conf 文件？

我的首选方法是在我的 C# ARI 应用程序中实现它，因为这会让我更好地控制会议。

Answer 1

您应该创建一些拨号计划来支持这一点，并要求拨号计划检查您的密码等

当然，在没有拨号方案支持的情况下也可以完成，但在这种情况下，任务就成为专家级别的任务，这样做没有真正的意义。

首先，我可以向您推荐《Asterisk：电话的未来》一书。

您可以使用 func_odbc、读取应用程序、CHANNEL 函数（针对 ip）