获取在1周内过生日的人员列表

Question

说我有一系列的生日

 var bdates = ['1956-12-03', '1990-03-09',...]

我将通过一个函数将每一个函数返回到今天(或从现在开始)7天内生日那天的日期？我现在拥有的是:

var bdays = _.map(bdates, function(date) {
  var birthDate = new Date(date);
  var current = new Date();
  var diff = current - birthDate; // Difference in milliseconds
  var sevenDayDiff = Math.ceil(diff/31557600000) - (diff/31557600000); //1000*60*60*24*365.25
  if (sevenDayDiff <= 0.01916495550992)
    return date;
  else
    return false;
});

值0.01995183087435是根据51周内的毫秒数除以52周内的毫秒数确定的,然后减去该比率应为'sevenDayDiff'变量.

不幸的是,我的JSFIDDLE并没有完全正确.这有很多问题.我的sevenDayDiff可能是错误的价值.还有闰年问题,即使我除以365.25.我可能只是以错误的方式解决这个问题.

这是在Web应用程序中进行的,因此管理员可以向7天内过生日的人发送电子邮件.欢迎任何提示或建议.

Answer 1

var bdates = ['1956-12-03', '1990-03-09', '1970-02-14'];

var now = moment('2015-02-10');
var birthDates = [];

bdates.forEach(function(birthDate) {
  var birthDay = moment(birthDate).year(now.year());
  var birthDayNextYear = moment(birthDate).year(now.year() + 1);
  var daysRemaining = Math.min(Math.abs(birthDay.diff(now, 'days')), Math.abs(birthDayNextYear.diff(now, 'days')));
  
  if((daysRemaining >= 0) && (daysRemaining <= 7)) {
    birthDates.push(birthDate);
  }
});

document.write(JSON.stringify(birthDates));

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