从1回到1,从2回到2,...,从11回到11,

Question

是否有Objective-c函数NSString *从a 返回a NSUInteger,即:

• 1 - > 1
• 2 - > 2
• ...
• 10 - > 10
• 21 - > 21
• ...
• 31 - > 31

范围从1到31.谢谢!

Answer 1

- (NSString *)stringFromInt:(int)num {
    NSString stringAddition;
    if (num%100 >= 11 && num%100 <= 13) {
        stringAddition = @"th";
    }
    else {
        switch (num % 10) {
            case 1: stringAddition = @"st"; break;
            case 2: stringAddition = @"nd"; break;
            case 3: stringAddition = @"rd"; break;
            default: stringAddition = @"th"; break;
        }
    }
    return [NSString stringWithFormat:@"%i%@", num, stringAddition];
}

编辑:
修正了11,12,13号问题.